recursion

MySQL recursive update trigger

旧城冷巷雨未停 提交于 2020-05-28 07:19:00
问题 I found a number of discussions about this, and it seems mySQL simply doesn't allow the use of recursive triggers. Other discussions advise against trying to do this, but I'm fairly confident in the design of my trigger, so it doesn't run the risk of an infinite loop. I guess I'm asking for confirmation on this limitation/design choice in mySQL, and any suggestions for an alternate approach to what I am trying to achieve. ---'PROBLEM'--- To sum up, I have a database that includes a contacts

MySQL recursive update trigger

帅比萌擦擦* 提交于 2020-05-28 07:18:51
问题 I found a number of discussions about this, and it seems mySQL simply doesn't allow the use of recursive triggers. Other discussions advise against trying to do this, but I'm fairly confident in the design of my trigger, so it doesn't run the risk of an infinite loop. I guess I'm asking for confirmation on this limitation/design choice in mySQL, and any suggestions for an alternate approach to what I am trying to achieve. ---'PROBLEM'--- To sum up, I have a database that includes a contacts

Ramda recursive merge based on keys' match

拈花ヽ惹草 提交于 2020-05-22 09:40:52
问题 I have two lists of nodes, who shaped like so: interface TreeNode { data: { name: string, sharedProp: boolean, oldProp: boolean }, children: TreeNode[], parents: TreeNode[], thereAreSomeShallowProps: any, } The full dataset would be an array of TreeNode What I'd like is to have a function that I can traverse down this tree, merging changes in a changes tree into the base tree. Some of the feature it'd need: Match the values of a specified key (in this case support multilevel keys), and merge

Project 2 Human Pyramid Calculations

偶尔善良 提交于 2020-05-17 07:52:50
问题 For simplicity we will assume that everyone in the pyramid weighs exactly 200 pounds. Person A at the top of the pyramid has no weight on her back. People B and C are each carrying half of person A's weight. That means that each of them is shouldering 100 pounds. Now, let's look at the people in the third row. Let’s begin by focusing on person E. How much weight is she supporting? Well, she’s directly supporting half the weight of person B (100 pounds) and half the weight of person E (100

How to write findMinimum of a lazy deleted Binary Search Tree in Java

旧巷老猫 提交于 2020-05-16 04:06:29
问题 I am writing a class for a Binary Search Tree in Java that uses lazy deletion (instead of removing the node from the tree, it sets a "deleted" flag to true) My question is, how would I implement a findMin function for a tree like this? The normal method of just going to the leftmost leaf wouldn't work because that lead may be "deleted". For example, A tree like this where you delete 20, 5, and 17 25 *20 30 *17 89 *5 should return 25 when you call findMin(). My implementation looks like this:

recursive sum of all the digits in a number

三世轮回 提交于 2020-05-15 21:49:10
问题 I am stuck in this exercise. Task: A digital root is the recursive sum of all the digits in a number. Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. This is only applicable to the natural numbers. Here's how it works: digital_root(16) 1 + 6 = 7 digital_root(942) 9 + 4 + 2 = 15 ... 1 + 5 =6 My approach is here. Any tips on how to properly return correct value? I would appreciate any help.

R: recursive tree algorithm with a random split

梦想与她 提交于 2020-05-15 12:19:11
问题 I'm interested in writing up a recursive binary tree algorithm. Given the following data where I've already sorted the covariate x mydata <- data.frame(x = c(10, 20, 25, 35), y = c(-10.5, 6.5, 7.5, -7.5)) > mydata x y 1 10 -10.5 2 20 6.5 3 25 7.5 4 35 -7.5 Suppose my final tree looks something like this: [-10.5, 6.5, 7.5, -7.5] / \ [-10.5] [6.5, 7.5, -7.5] / \ [6.5, 7.5] [ -7.5] I want the final output of my function to return a list that contains all of the nodes: > final_tree [[1]] [[1]][[1

R: recursive tree algorithm with a random split

南楼画角 提交于 2020-05-15 12:18:12
问题 I'm interested in writing up a recursive binary tree algorithm. Given the following data where I've already sorted the covariate x mydata <- data.frame(x = c(10, 20, 25, 35), y = c(-10.5, 6.5, 7.5, -7.5)) > mydata x y 1 10 -10.5 2 20 6.5 3 25 7.5 4 35 -7.5 Suppose my final tree looks something like this: [-10.5, 6.5, 7.5, -7.5] / \ [-10.5] [6.5, 7.5, -7.5] / \ [6.5, 7.5] [ -7.5] I want the final output of my function to return a list that contains all of the nodes: > final_tree [[1]] [[1]][[1

Recursive inorder traversal of a binary search tree

百般思念 提交于 2020-05-15 08:53:05
问题 I want to implement a recursive inorder in a binary search tree (BST). I built a tree using two structs: Node and Tree . My code has not worked so far, mainly because of a type mismatch in Node::inorder . pub struct Node<T> { value: T, left: Option<Box<Node<T>>>, right: Option<Box<Node<T>>>, } pub struct Tree<T> { root: Option<Box<Node<T>>>, } impl<T: Ord> Tree<T> { /// Creates an empty tree pub fn new() -> Self { Tree { root: None } } pub fn inorder(&self) -> Vec<&T> { self.root.as_ref().map

Trying to Use Recursion to solve Fibonacci (javascript)

随声附和 提交于 2020-05-15 08:05:12
问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function