recursion

问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function

问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function

问题 C language In the C programming language, it's easy to have tail recursion : int foo(...) { return foo(...); } Just return as is the return value of the recursive call. It is especially important when this recursion may repeat a thousand or even a million times. It would use a lot of memory on the stack . Rust Now, I have a Rust function that might recursively call itself a million times: fn read_all(input: &mut dyn std::io::Read) -> std::io::Result<()> { match input.read(&mut [0u8]) { Ok ( 0

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I have this cloud function: import pLimit from "p-limit"; const syncNotificationsAvatar = async ( userId: string, change: Change<DocumentSnapshot> ) => { if (!change.before.get("published") || !change.after.exists) { return; } const before: Profile = change.before.data() as any; const after: Profile = change.after.data() as any; const keysToCompare: (keyof Profile)[] = ["avatar"]; if ( arraysEqual( keysToCompare.map((k) => before[k]), keysToCompare.map((k) => after[k]) ) ) { return; } const

问题 I was asked to calculate the following nested root expression using recursion only. I wrote the code below that works, but they allowed us to use only one function and 1 input n for the purpose and not 2 like I used. Can someone help me transform this code into one function that will calculate the expression? cant use any library except functions from <math.h> . output for n=10: 1.757932 double rec_sqrt_series(int n, int m) { if (n <= 0) return 0; if (m > n) return 0; return sqrt(m + rec_sqrt