number 622.08E6 interpretation in C

问题

I recently came across a C code (working by the way) where I found

freq_xtal = ((622.08E6 * vcxo_reg_val->hiv * vcxo_reg_val->n1)/(temp_rfreq));

From my intuition it seems that 622.08E6 should mean 622.08 x 10^6. Is this assumption correct?

I tried googling for a similar example where E notation is used in a C program. Surprisingly couldn't find any result

回答1:

Yes, that is correct. It works just like an old-school scientific calculator.

In this case, it looks like you're dealing with a 622.08MHz signal and a VCOX on a PLL?

来源：https://stackoverflow.com/questions/19781570/number-622-08e6-interpretation-in-c