- 查看岗位是teacher的员工姓名、年龄
- 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
- 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
- 查看岗位描述不为NULL的员工信息
- 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
- 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
- 查看岗位是teacher且名字是jin开头的员工姓名、年薪
先创建表格slt:
mysql> create table slt( -> num int auto_increment primary key, -> name char(10), -> job char(10), -> age int, -> salary int, -> descrip char(128)not null default '' -> )charset=utf8;
查看列表
mysql> desc slt; +---------+-----------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+-----------+------+-----+---------+----------------+ | num | int(11) | NO | PRI | NULL | auto_increment | | name | char(10) | YES | | NULL | | | job | char(10) | YES | | NULL | | | age | int(11) | YES | | NULL | | | salary | int(11) | YES | | NULL | | | descrip | char(128) | NO | | | | +---------+-----------+------+-----+---------+----------------+ 6 rows in set (0.02 sec)
此时表为空
mysql> select * from slt; Empty set (0.00 sec)
插入数据:
mysql> insert into tlt(name, job, age, salary,descrip) values -> ('Tom', 'teacher', 30, 20000, level2 ), -> ('frank', 'teacher', 31, 21000, level2 ), -> ('jack', 'teacher', 32, 22000, level2 ), -> ('jhon', 'asistant', 23, 8000, '' ), -> ('hugo', 'manager', 45, 30000, level4 ), -> ('jinhisan', 'teacher', 26, 9000, level1 ) -> ; Query OK, 6 row affected (0.01 sec)
1、查看岗位是teacher的员工姓名、年龄
mysql> select distinct name, age from slt where job='teacher';
2、查看岗位是teacher且年龄大于30岁的员工姓名、年龄
mysql> select distinct name, age from slt where job='teacher' and age>30;
3、查看岗位是teacher且薪资在1000-9000范围内的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job='teacher' and (salary>1000 and salary<9000);
4、查看岗位描述不为NULL的员工信息
mysql> select * from slt where descrip!=NULL ;
5、查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job='teacher' and (salary=10000 or salary=9000 or salary=30000);
6、查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job='teacher' and (salary not in (10000,9000,30000));
7、查看岗位是teacher且名字是'jin'开始的员工姓名、年薪
mysql> select * from slt where job='teacher' and name like 'jin%' ;