sorted

fastest way to determine if an element is in a sorted array

馋奶兔 提交于 2019-11-30 19:45:36
I have an array of sorted ints with a 1,000 or more values (could be up to 5000+). I need to write a function that receives an int and returns a bool based on the element being in the array. I know I can write a for loop with a break, I know I can use jquery .InArray. What would be the best way to implement this, KNOWING that the array is sorted. Thanks. Knowing that the array is sorted a binary search would be the best approach. I think you'd want to use a binary search routine. A binary search routine is whereas a linear search is, on average, . There are many variations to choose form. Here

JPA/hibernate sorted collection @OrderBy vs @Sort

断了今生、忘了曾经 提交于 2019-11-30 10:29:47
问题 I would like to have a collection of child objects (here cat-kitten example) that are ordered. And keep their order on adding of new elements. @Entity public class Cat { @OneToMany(mappedBy = "cat", cascade = CascadeType.ALL) @OrderBy("name ASC") private List<Kitten> kittens; public void setKittens(List<Kitten> kittens) { this.kittens = kittens; } public List<Kitten> getKittens() { return kittens; } } When I do cat.getKittens.add(newKitten) the order by name will be broken. Is it possible to

JavaFX: TableView: Arrow for a column sorted by default

可紊 提交于 2019-11-30 08:50:04
I have a simple java fx application which has a table view. The table view shows some data that is sorted in a certain order. Is there a way to show the arrow(by default) indicating that the data has been sorted in that order? My code is below: import java.util.Collections; import javafx.application.Application; import javafx.beans.property.SimpleIntegerProperty; import javafx.beans.property.SimpleStringProperty; import javafx.collections.FXCollections; import javafx.collections.ObservableList; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.control.Label; import

python sort list of json by value

ぐ巨炮叔叔 提交于 2019-11-30 06:01:27
I have a file consists of JSON, each a line, and want to sort the file by update_time reversed. sample JSON file: { "page": { "url": "url1", "update_time": "1415387875"}, "other_key": {} } { "page": { "url": "url2", "update_time": "1415381963"}, "other_key": {} } { "page": { "url": "url3", "update_time": "1415384938"}, "other_key": {} } want output: { "page": { "url": "url1", "update_time": "1415387875"}, "other_key": {} } { "page": { "url": "url3", "update_time": "1415384938"}, "other_key": {} } { "page": { "url": "url2", "update_time": "1415381963"}, "other_key": {} } my code: #!/bin/env

Sorted hash table (map, dictionary) data structure design

两盒软妹~` 提交于 2019-11-30 04:24:13
Here's a description of the data structure: It operates like a regular map with get , put , and remove methods, but has a sort method that can be called to sorts the map. However, the map remembers its sorted structure, so subsequent calls to sort can be much quicker (if the structure doesn't change too much between calls to sort ). For example: I call the put method 1,000,000 times. I call the sort method. I call the put method 100 more times. I call the sort method. The second time I call the sort method should be a much quicker operation, as the map's structure hasn't changed much. Note

C++ Calculating the Mode of a Sorted Array

冷暖自知 提交于 2019-11-29 19:51:39
问题 I have to write a C++ code that finds the median and mode of an array. I'm told that it's much easier to find the mode of an array AFTER the numbers have been sorted. I sorted the function but still cannot find the mode. int counter = 0; for (int pass = 0; pass < size - 1; pass++) for (int count = pass + 1; count < size; count++) { if (array [count] == array [pass]) counter++; cout << "The mode is: " << counter << endl; 回答1: If the array has been sorted already, you can count the occurrences

Algorithm to merge multiple sorted sequences into one sorted sequence in C++

≯℡__Kan透↙ 提交于 2019-11-29 13:24:26
I am looking for an algorithm to merge multiple sorted sequences, lets say X sorted sequences with n elements, into one sorted sequence in c++ , can you provide some examples? note: I do not want to use any library There are three methods that do the merging :- Suppose you are merging m lists with n elements each Algorithm 1 :- Merge lists two at a time. Use merge sort like merge routine to merge as the lists are sorted. This is very simple to implement without any libraries. But takes time O(m^2*n) which is small enough if m is not large. Algorithm 2:- This is an improvement over 1. where we

Will a Python dict with integers as keys be naturally sorted?

故事扮演 提交于 2019-11-29 13:09:52
If I create a Python dict which uses integers as keys, can I safely assume that iterating over the dict will retrieve items in order according to key value? i.e. will my_dict = {} for x in range(0,100): my_dict[x] = str(x) for item in my_dict.items(): print item always result in printing the list in order of key value? In short, no. I'm betting you noted that dictionaries use the hashes of keys as indexes in to an array, and since ints hash to their own values, you inferred that inserted values would end up in order by key if their keys are integers. While the first 2 parts of that statement

JavaFX: TableView: Arrow for a column sorted by default

主宰稳场 提交于 2019-11-29 12:32:56
问题 I have a simple java fx application which has a table view. The table view shows some data that is sorted in a certain order. Is there a way to show the arrow(by default) indicating that the data has been sorted in that order? My code is below: import java.util.Collections; import javafx.application.Application; import javafx.beans.property.SimpleIntegerProperty; import javafx.beans.property.SimpleStringProperty; import javafx.collections.FXCollections; import javafx.collections

Native C# support for checking if an IEnumerable is sorted?

戏子无情 提交于 2019-11-29 11:19:41
Is there any LINQ support for checking if an IEnumerable<T> is sorted? I have an enumerable that I want to verify is sorted in non-descending order, but I can't seem to find native support for it in C#. I've written my own extension method using IComparables<T> : public static bool IsSorted<T>(this IEnumerable<T> collection) where T : IComparable<T> { Contract.Requires(collection != null); using (var enumerator = collection.GetEnumerator()) { if (enumerator.MoveNext()) { var previous = enumerator.Current; while (enumerator.MoveNext()) { var current = enumerator.Current; if (previous.CompareTo