sorted

Python: Determine if an unsorted list is contained in a 'list of lists', regardless of the order to the elements

跟風遠走 提交于 2019-12-02 10:33:13
I have a similar question to this question: Determine if 2 lists have the same elements, regardless of order? What is the best/quickest way to determine whether an unsorted list list1 is contained in a 'list of lists' myListOfLists , regardless of the order to the elements in list1 ? My attempt is wrapped up in the function doSomething(...) which I call many times: def doSomething(myListOfLists, otherInputs): list1 = [] ... # do something here with `otherInputs' ... # which gives `list1' some values # now only append `list1' to `myListOfLists' if it doesn't already exist # and if it does exist

Print an ordered linked list

空扰寡人 提交于 2019-12-02 08:57:32
问题 Just did some editing on it, i tried what you said but it didnt work, so i tried something i am a little more familiar with but it doesnt seem to work correctly. It prints the information weirdly then crashes.. For exmaple: When i imput 9-8-7-6-5-4-3-2-1 then 0 to print, it prints back to me 0-0-0-9-1-2-3-4-5-6-7-8 and then crashes? when i imput 1-2-3-4-5-6-7-8-9 then 0 to print, it prints back to me 0-0-0-1-2-3-4-5-6-7-8-9 and then crashes. #include <stdio.h> #include <stdlib.h> struct

Sort a list numerically in Python

我们两清 提交于 2019-12-02 04:15:25
问题 So I have this list, we'll call it listA. I'm trying to get the [3] item in each list e.g. ['5.01','5.88','2.10','9.45','17.58','2.76'] in sorted order. So the end result would start the entire list over again with Santa at the top. Does that make any sense? [['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17

Index of element in sorted()

╄→尐↘猪︶ㄣ 提交于 2019-12-02 03:24:52
When you call sorted(<#source: C#>, <#isOrderedBefore: (C.Generator.Element, C.Generator.Element) -> Bool##(C.Generator.Element, C.Generator.Element) -> Bool#>) you can access the two source elements for comparison via $0 and $1 . But how can I determine the index from where they were taken from the source? You could pass into sorted not a collection of elements, but the indices of the elements: let a = ["hello","i","must","be","going"] let idxs = sorted(indices(a)) { a[$0] < a[$1] } // produces [3, 4, 0, 1, 2] Or, if you don't like capturing a and wanted the elements themselves passed into

Sort a list numerically in Python

ぐ巨炮叔叔 提交于 2019-12-02 02:08:11
So I have this list, we'll call it listA. I'm trying to get the [3] item in each list e.g. ['5.01','5.88','2.10','9.45','17.58','2.76'] in sorted order. So the end result would start the entire list over again with Santa at the top. Does that make any sense? [['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17.20', u'14.44', '2.76']] If you want to return the complete list in sorted order, this may work. This

Indexing using Redis sorted sets

房东的猫 提交于 2019-12-01 17:09:05
问题 I would like to get some feedback and suggestions regarding two approaches I'm considering to implementing searchable indexes using Redis sorted sets. Situation and objective We currently have some key-value tables we're storing in Cassandra, and which we would like to have indexes for. For example, one table would contain records of people, and the Cassandra table would have id as its primary key, and the serialized object as the value. The object would have fields such as first_name, last

23. Merge k Sorted Lists

瘦欲@ 提交于 2019-12-01 10:26:31
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6直接复用归并排序即可 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeKLists(vector<ListNode*>& lists) { ListNode *res=NULL; for(int i=0;i<lists.size();++i) { if(NULL==res) { res=lists[i]; continue; } res=merge(res,lists[i]); } return res; } ListNode* merge(ListNode *l1,ListNode *l2) { if(NULL==l1)return

How to sort an ArrayList with object using stream().sorted()

末鹿安然 提交于 2019-12-01 05:20:59
I am having real trouble with using stream and sorted to sort my ArrayList and hope someone can help out. The code uses Croatian words, but I don't think that will be a problem for someone who understands what I mean. This is the ArrayList ArrayList<Publikacija> listaPublikacija = new ArrayList<>(); listaPublikacija.add(prvaKnjiga); listaPublikacija.add(drugaKnjiga); listaPublikacija.add(prviCasopis); listaPublikacija.add(drugiCasopis); In my assignment I am supposed to sort these objects above by getCijena() which is double. This is the best I got and it still doesn't sort it as it should...

How to force refresh the DataGridView's content?

此生再无相见时 提交于 2019-12-01 04:08:37
问题 I want to make a sorted datagridview input. The following code snippet doesn't quite cut it; even if i put a grd.Refresh, the datagridview doesn't show its updated values. If i press arrow down key and go up again, the grid is refreshing. Is there any other way i can force refresh to datagridview's content? using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Text; using System.Windows.Forms; namespace

Python sorted() function not working the way it should

守給你的承諾、 提交于 2019-11-30 21:03:00
问题 Basically I have a nested list that I am trying to sort through the 1'st index I copied the way that the python howto says how to do it but it doesn't seem to work and I don't understand why: code from the website: >>> student_tuples = [ ('john', 'A', 15), ('jane', 'B', 12), ('dave', 'B', 10), ] >>> sorted(student_tuples, key=lambda student: student[2]) # sort by age [('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)] My code: def print_scores(self): try: #opening txt and reading data