invite

问题 I need to send SIP message using Python sockets, I've made that client sends something to server but I'm not able to make that client sends a SIP message INVITE to server #!/usr/bin/python import socket R_IP = '192.168.2.1' R_PORT = 5060 message = 'INVITE sip:user1110000000350@.com SIP/2.0 To: <sip:user4110000000350@whatever.com>\x0d\x0aFrom: sip:user9990000000000@rider.com;tag=R400_BAD_REQUEST;taag=4488.1908442942.0\x0d\x0aP-Served-User: sip:user4110000000350@whatever.com\x0d\x0aCall-ID:

问题 I need to send SIP message using Python sockets, I've made that client sends something to server but I'm not able to make that client sends a SIP message INVITE to server #!/usr/bin/python import socket R_IP = '192.168.2.1' R_PORT = 5060 message = 'INVITE sip:user1110000000350@.com SIP/2.0 To: <sip:user4110000000350@whatever.com>\x0d\x0aFrom: sip:user9990000000000@rider.com;tag=R400_BAD_REQUEST;taag=4488.1908442942.0\x0d\x0aP-Served-User: sip:user4110000000350@whatever.com\x0d\x0aCall-ID:

问题 I need to add an invite users functionality to my social networking application so users can invite contacts from their hotmail or yahoo accounts. How do I do this and are there any free open source libraries that do this? 回答1: Depending on the service you wish to get the contact information from they might already provide a published API for you. For example, Yahoo has a contact list API you could use: http://developer.yahoo.com/social/rest_api_guide/contact_api.html Google also has one:

问题 In my app i have to add an intent to share my app. I looked through Tez, which shares the app icon along with a text which contains a hyperlink. How to achieve this? 回答1: private void prepareShareIntent(Bitmap bmp) { Uri bmpUri = getLocalBitmapUri(bmp); // see previous remote images section // Construct share intent as described above based on bitmap Intent shareIntent = new Intent(); shareIntent = new Intent(); shareIntent.setPackage("com.whatsapp"); shareIntent.setAction(Intent.ACTION_SEND)

问题 Situation: user A send invitation to my fb app to his friends X , Y and Z . Users X and Y has accepted invitations, but user Z not. How can I track haw many users accepted invitations? I want to take some privileges for user A based on accepted invitations count. Is there any method to track sender_id when invitation accepted? 回答1: Don't bother, it's not allowed by the policy. Per section V.1. You must not incentivize users to grant additional permissions or use Application Integration Points

问题 I'm facing difficulty inviting a friend to the match. GKMatchRequest *request = [[[GKMatchRequest alloc] init] autorelease]; request.minPlayers = 2; request.maxPlayers = 2; request.playersToInvite = [NSArray arrayWithObjects: @"G:1102359306",nil ]; // GKMatchmakerViewController *mv = [[GKMatchmakerViewController alloc] initWithMatchRequest:request]; // [self presentModalViewController:mv animated:YES]; [[GKMatchmaker sharedMatchmaker] findMatchForRequest:request withCompletionHandler:^

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . What ways to invite user friends on facebook connected website you know? During last days I've found following methods: Just post message on user wall. But it's not targeted message. Send facebook messages to friends using message dialog. But it can lead app to ban with following reason "Facebook messages is a

问题 In my current .NET and FBML-based facebook app, I have some code that looks like this: <fb:request-form action="http://mysite.com/InvitesSent.aspx" method="POST" invite="true" type="SomeType" content="Here is an invite to <fb:req-choice url='http://mysite.com?<%=Params %>' label='My site' />"> <fb:multi-friend-selector max="20" actiontext="Invite your friends!" showborder="false" rows="4" bypass="cancel" email_invite="false" exclude_ids="" /> </fb:request-form> This pops up the multi-friend

问题 I would really appreciate once again if someone could help me out! I'm working on a registration form which works fine, but I wanted to implement an invitation code check in there, too. I never did that before and since I'm a newbie I just searched for a solution, tried to understand and to adopt...so please don't judge me :) I'm just trying to learn with each step! So quick what I'm trying to do -> user types in an invitation code 2.if incorrect (checked in the database then -> error msg) if

问题 i'm using firebase dynamic links to invite friends to my app. Everything works great. Clicking the invitation link leads me to the playstore. When i install the app and wait until its done the playstore shows me the button "Continue". When i click this button, the app opens and i receive the deeplink to track the invitation. But when i install the app, close the playstore and open the app through the app drawer i'm NOT receiving the deeplink. Is this an expected behavior? My problem is, that