frequency

How to play two sine wave on left and right channel separately with 16-bit format?

由 北慕城南 提交于 2019-12-23 04:23:15
问题 I need to generate 2 sine wave tones with different frequency and play them separately into right and left channel in stereo mode on Android. This is my code: int sample; double sampleRate; double duration; double time; double f1; double f2; double amplitude1; double amplitude2; double sineWave1; double sineWave2; float[] buffer1; float[] buffer2; byte[] byteBuffer1; byte[] byteBuffer2; byte[] byteBufferFinal; int bufferIndex; short x; short y; AudioTrack audioTrack; @Override public void

Simple R (histogram) from counted csv file [duplicate]

由 夙愿已清 提交于 2019-12-23 02:52:20
问题 This question already has answers here : Creating a histogram using aggregated data (4 answers) Closed 6 years ago . HI Guys I'm trying to plot a frequency graph of a simple 2d file file:data.csv terms,count 1,10 5,17 3,28 9,30 I want the first col(terms) to be the x-axis and the col(count) be the height/percentage. I've tried this: d<-read.csv(data.csv) hist(d) Error in hist.default(d) : 'x' must be numeric dc<-table(d) hist(dc) <-- wrong result. 回答1: The problem is that hist() needs a

如何精准的获得时钟频率计算耗时——QueryPerformanceFrequency

由 ⅰ亾dé卋堺 提交于 2019-12-22 12:02:05
时间处理 在处理一些获得时间的问题时，可以用clock（）函数简单的获得时钟，但是进度往往是不够的，这个时候可以用 QueryPerformanceFrequency（&frequency）获得更精确的时钟 1.clock()，字面精度1ms，实际精度是操作系统的时间片，windows下单核10ms，双核15ms 2.QueryPerformenceCounter，字面精度100ns（0.1us），实际精度100us左右 对于毫秒级 用2个都可以，对于us级建议用QueryPerformenceCounter 下面介绍QueryPerformenceCounter的快速用法： # include <iostream> # include <windows.h> using namespace std ; LARGE_INTEGER frequency ; void function ( ) { cout << "cost time=" ; } int main ( ) { double dff , begin_ , _end , time ; QueryPerformanceFrequency ( & frequency ) ; //获得时钟频率 dff = ( double ) frequency . QuadPart ; //取得频率*/

How to define frequency of SyncAdapter updates on android?

由 泄露秘密 提交于 2019-12-22 10:34:00
问题 ContentProvided defined for synchronization is dummy (in accordance with this approach). 回答1: If API > 8, (95% of devices) use ContentResolver.addPeriodicSync() If API = 7, (5.5% of devices as of Mar 2102) create a service with a periodic timer callback, and call ContentResolver.requestSync() . API < 6 does not support syncAdapter, so no worries. 来源： https://stackoverflow.com/questions/5525593/how-to-define-frequency-of-syncadapter-updates-on-android

How can I resize the boxes in a boxplot created with R and ggplot2 to account for different frequencies amongst different boxplots? [duplicate]

由 六月ゝ 毕业季﹏ 提交于 2019-12-22 08:42:02
问题 This question already has answers here : Is there an equivalent in ggplot to the varwidth option in plot? (2 answers) Closed 5 years ago . I have a boxplot that I made in R with ggplot2 analagous to the sample boxplot below. The problem is, for the values on the y axis (in this sample, the number of cylinders in the car) I have very different frequencies -- I may have included 2 8 cylinder cars, but 200 4 cylinder cars. Because of this, I'd like to be able to resize the boxplots (in this case

How can I resize the boxes in a boxplot created with R and ggplot2 to account for different frequencies amongst different boxplots? [duplicate]

由 给你一囗甜甜゛ 提交于 2019-12-22 08:41:37
问题 This question already has answers here : Is there an equivalent in ggplot to the varwidth option in plot? (2 answers) Closed 5 years ago . I have a boxplot that I made in R with ggplot2 analagous to the sample boxplot below. The problem is, for the values on the y axis (in this sample, the number of cylinders in the car) I have very different frequencies -- I may have included 2 8 cylinder cars, but 200 4 cylinder cars. Because of this, I'd like to be able to resize the boxplots (in this case

Is there an library in Java for emitting a certain frequency constantly?

由 寵の児 提交于 2019-12-22 07:28:15
问题 Right, well. First time I'm actually using Java to fix a problem. I bought a new headphone set called Sennheiser 120 HD; but there's an issue. If there isn't a constant emission of audio then the base for the headphones will eventually time out and turn off. The headphones are spammed with static, which is horrible on the ears. The solution to this for me currently is playing music 24/7 to prevent the static of death. Maybe I'm weird, but I don't want to listen to music 24/7. I believe a

Is there an library in Java for emitting a certain frequency constantly?

由 纵饮孤独 提交于 2019-12-22 07:28:11
问题 Right, well. First time I'm actually using Java to fix a problem. I bought a new headphone set called Sennheiser 120 HD; but there's an issue. If there isn't a constant emission of audio then the base for the headphones will eventually time out and turn off. The headphones are spammed with static, which is horrible on the ears. The solution to this for me currently is playing music 24/7 to prevent the static of death. Maybe I'm weird, but I don't want to listen to music 24/7. I believe a

ValueWarning: No frequency information was provided, so inferred frequency MS will be used

由 那年仲夏 提交于 2019-12-22 05:03:16
问题 I try to fit Autoregression by sm.tsa.statespace.SARIMAX. But I meet a warning, then I want to set frequency information for this model. Who used to meet it, can you help me ? fit1 = sm.tsa.statespace.SARIMAX(train.Demand, order=(1, 0, 0), enforce_stationarity=False, enforce_invertibility=False).fit() y_hat['AR'] = fit1.predict(start="1975-01-01", end="1975-12-01", dynamic=True) plt.figure(figsize=(16,8)) plt.plot( train['Demand'], label='Train') plt.plot(test['Demand'], label='Test') plt

Converting word frequency to a graphical histogram in python

由 只愿长相守 提交于 2019-12-22 00:40:31
问题 This is what I have right now, thanks to Pavel Anossov. I am trying to convert the word frequency that has been outputed into asterisks. import sys import operator from collections import Counter def candidateWord(): with open("sample.txt", 'r') as f: text = f.read() words = [w.strip('!,.?1234567890-=@#$%^&*()_+')for w in text.lower().split()] #word_count[words] = word_count.get(words,0) + 1 counter = Counter(words) print("\n".join("{} {}".format(*p) for p in counter.most_common()))
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