chain

问题 How can I get a signing chain from a CMSSignedData (BouncyCastle) to verify it with the signing chain store? Certificate[] storeCertChain = store.getCertificateChain(alias) Isn't there a command or something like this I can get the signing chain of the data? Or get the certificate from it and there from the signing chain? 回答1: The chain of the certificate used to sign might be in the CMSSignedData , but it's not mandatory. According to RFC 3852, a CMS SignedData has the following structure

问题 I'm using the moq framework by Daniel Cazzulino, kzu Version 4.10.1. I want to moq so i can test a particular part of functionality (below is the simplistic version of the Code i could extract) The fluent/chain method so are designed so you can get object by an Id and include any additional information if required. i'm having some trouble fetching the correct object when the function is calling the moq'ed method, which is currently returning the last moq'ed object which is wrong /*My current

问题 When I route a task to a particular queue it works: task.apply_async(queue='beetroot') But if I create a chain: chain = task | task And then I write chain.apply_async(queue='beetroot') It seems to ignore the queue keyword and assigns to the default 'celery' queue. It would be nice if celery supported routing in chains - all tasks executed sequentially in the same queue. 回答1: I do it like this: subtask = task.s(*myargs, **mykwargs).set(queue=myqueue) mychain = celery.chain(subtask, subtask2, .

问题 So every mention of __proto__ is usually followed by a reference to Brendan Eich's plea not to use it. I've been playing around with some reflection in Typescript, navigating the prototype chain of a class down to a provided ancestor class using it, and would love to inject a single prototype property holding class metadata. Does anyone have any specifics on the performance overhead I might incur, or a solution that doesn't rely on __proto__? EDIT - Updated with code. This is just a contrived

问题 I'm working with R in some biology-behavioural problems, and I have a transition matrix which I want to plot in a certain way. I'm using the markovchain package, which makes easy the visualization. This is a test-code and it's output. > a<-array(0.25,dim = c(4,4)) > markov<-new("markovchain",transitionMatrix=a,states=c("a","b","c","d"), name="test") > markov test A 4 - dimensional discrete Markov Chain defined by the following states: a, b, c, d The transition matrix (by rows) is defined as

问题 for a code like this let anotherFolder='whatever'; let anotherFolder2='whatever'; chrome.bookmarks.create( {title:'whatever2'}, function( parentFolder ) { chrome.bookmarks.move( anotherFolder, {parentId: parentFolder.id}, function() { chrome.bookmarks.removeTree( anotherFolder2, function() { resolve(); }); }); }); can I transform it to chain functions? Something like let anotherFolder='whatever'; let anotherFolder2='whatever'; return new Promise(function(resolve){ chrome.bookmarks.create(

问题 for a code like this let anotherFolder='whatever'; let anotherFolder2='whatever'; chrome.bookmarks.create( {title:'whatever2'}, function( parentFolder ) { chrome.bookmarks.move( anotherFolder, {parentId: parentFolder.id}, function() { chrome.bookmarks.removeTree( anotherFolder2, function() { resolve(); }); }); }); can I transform it to chain functions? Something like let anotherFolder='whatever'; let anotherFolder2='whatever'; return new Promise(function(resolve){ chrome.bookmarks.create(

问题 Given the input: x = ['foo bar', 'bar blah', 'black sheep'] I could do this to get the count of each word in the list of space delimited string: from itertools import chain from collections import Counter c = Counter(chain(*map(str.split, x))) Or I could simple iterate through and get: c = Counter() for sent in x: for word in sent.split(): c[word]+=1 [out]: Counter({'bar': 2, 'sheep': 1, 'blah': 1, 'foo': 1, 'black': 1}) The question is which is more efficient if the input list of string is

问题 Given the input: x = ['foo bar', 'bar blah', 'black sheep'] I could do this to get the count of each word in the list of space delimited string: from itertools import chain from collections import Counter c = Counter(chain(*map(str.split, x))) Or I could simple iterate through and get: c = Counter() for sent in x: for word in sent.split(): c[word]+=1 [out]: Counter({'bar': 2, 'sheep': 1, 'blah': 1, 'foo': 1, 'black': 1}) The question is which is more efficient if the input list of string is

问题 I have this text file where I am reading each line into a std::vector<std::pair> , handgun bullets bullets ore bombs ore turret bullets The first item depends on the second item. And I am writing a delete function where, when the user inputs an item name, it deletes the pair containing the item as second item. Since there is a dependency relationship, the item depending on the deleted item should also be deleted since it is no longer usable. For example, if I delete ore , bullets and bombs