chain

问题 If I have many validators against my entity, can I somehow specify one that it stops the rest if it fails? IE: there's no point checking Permissions if it fails NotBlank. Alternatively, if its not built in, perhaps theres a way to signal the graph walker to stop, and I can put in a validator that checks for prior failures and stops propagation through the graph. 回答1: If you set the validation in ./app/config/validation.yml then SF2 will validate as the order of validations in the file. Once a

问题 I want to find ALL the paths starting and ending from/to a specific node. I would like that each node in a path appears only once. For example, in a graph like this: (a)-[:REL]->(b)-[:REL]->(c)-[:REL]->(a) (a)-[:REL]->(e)-[:REL]->(f)-[:REL]->(a) (e)-[:REL]->(b) grafically: e → b ↙ ↖ ↗ ↘ f → a ← c Cypher code: CREATE (a { name:'A' })-[:REL]->(b {name:'B'})-[:REL]->(c { name:'C' }) -[:REL]->(a)-[:REL]->(e {name:'E'})-[:REL]->(f {name:'F'})-[:REL]->(a), (e)-[:REL]->(b) I would like that the

问题 Update: this issue was a result of jQuery 1.7 vs 1.8. Do not ever use promises in 1.7 beacuse they aren't chainable with returning a promise inside a .then . 1.8 looks like they didn't mess it up. http://jsfiddle.net/delvarworld/28TDM/ // make a promise var deferred = $.Deferred(); promise = deferred.promise(); // return a promise, that after 1 second, is rejected promise.then(function(){ var t = $.Deferred(); setTimeout(function() { console.log('rejecting...'); t.reject(); }, 1000); return t

问题 I've been running into a couple of problems with javascript promises, particularly with stacked chains. Can anyone explain to me the difference (if there is any!) between these different implementations? IMPLEMENTATION 1 var serverSidePromiseChain; serverSidePromiseChain = async().then(function(response) { console.log('1', response); return response; }).then(function(response) { console.log('2', response); return true; }).then(function(response) { console.log('3', response); // response

问题 Evolving from Javascript, spliced FileReader for large files with Promises, how?, which showed me how a Promise can also resolve a function, now I am stuck with the same but inside an Array.reduce function. The goal is that I want to upload a file (which already does) within an array, where each array item (a file) is uploaded sequentially (i.e. controlled through promises). Then, I understand that the answer is somehow in http://www.html5rocks.com/en/tutorials/es6/promises/?redirect_from

问题 I using Hadoop Map/Reduce using Java Suppose, I have completed a whole map/reduce job. Is there any way I could repeat the whole map/reduce part only, without ending the job. I mean, I DON'T want to use any chaining of the different jobs but only only want the map/reduce part to repeat. Thank you! 回答1: So I am more familiar with hadoop streaming APIs but approach should translate to the native APIs. In my understanding what you are trying to do is run the several iterations of same map() and

问题 Can you give a more simplified explanation of these two methods chain() and chain.from_iterable from itertools ? I have searched the knowledge base and as well the python documentation but i got confused. I am new to python that's why I am asking a more simplified explanation regarding these. Thanks! 回答1: You can chain sequences to make a single sequence: >>> from itertools import chain >>> a = [1, 2, 3] >>> b = ['a', 'b', 'c'] >>> list(chain(a, b)) [1, 2, 3, 'a', 'b', 'c'] If a and b are in

问题 If I have a list of list of list of tuples of two strings. I want to flatten it out to a non-nested list of tuples, I could do this: >>> from itertools import chain >>> lst_of_lst_of_lst_of_tuples = [ [[('ab', 'cd'), ('ef', 'gh')], [('ij', 'kl'), ('mn', 'op')]], [[('qr', 'st'), ('uv', 'w')], [('x', 'y'), ('z', 'foobar')]] ] >>> lllt = lst_of_lst_of_lst_of_tuples >>> list(chain(*list(chain(*lllt)))) [('ab', 'cd'), ('ef', 'gh'), ('ij', 'kl'), ('mn', 'op'), ('qr', 'st'), ('uv', 'w'), ('x', 'y'),

问题 I would like to do a method chain, for example like this: Car myCar = new Car(); // Chaining myCar.config.engine.cylinders("4"); But how do I do the chaining, without using parentheses in "config" or "engine"? I can only figure out to do it like this: myCar.config().engine().cylinders("4"); 回答1: You can do this by declaring Config property in your Car class. Then Engine property in CarConfig class, like this: public class Car { public CarConfig Config { get; set; } } Then you can chain the

问题 Like in this other question, I want to create a celery group from a list that's returned by a celery task. The idea is that the first task will return a list, and the second task will explode that list into concurrent tasks for every item in the list. The plan is to use this while downloading content. The first task gets links from a website, and the second task is a chain that downloads the page, processes it, and then uploads it to s3. Finally, once all the subpages are done, the website is