问题
Why does it (apparently) make a difference whether I pass null
as an argument directly, or pass an Object
that I assigned the value null
?
Object testVal = null;
test.foo(testVal); // dispatched to foo(Object)
// test.foo(null); // compilation problem -> \"The method foo(String) is ambiguous\"
public void foo(String arg) { // More-specific
System.out.println(\"foo(String)\");
}
public void foo(Object arg) { // Generic
System.out.println(\"foo(Object)\");
}
In other words, why is the (commented-out) second call to foo(...)
not dispatched to foo(Object)
?
Update: I use Java 1.6. I could compile Hemal\'s code without problems, but mine still doesn\'t compile. The only difference I see is that Hemal\'s methods are static while mine are not. But I really don\'t see why this should make a difference...?
Update 2: Solved. I had another method foo(Runnable) in my class, so the dispatcher couldn\'t unambiguously select the single most specific method. (See my comment in Hemal\'s second answer.) Thanks everyone for your help.
回答1:
Which version of Java are you using? With 1.6.0_11 the code (pasted below) compiles and runs.
I am sure its obvious why foo(testVal)
goes to foo(Object)
.
The reason why foo(null)
goes to foo(String)
is a little complex. The constant null
is of type nulltype
, which is a subtype of all types. So, this nulltype
extends String
, which extends Object
.
When you call foo(null)
compiler looks for the overloaded method with most specific type. Since String
is more specific then Object
that is the method that gets called.
If you had another overload that was as specific as String, say foo(Integer)
then you would get a ambiguous overload error.
class NullType {
public static final void main(final String[] args) {
foo();
}
static void foo()
{
Object testVal = null;
foo(testVal); // dispatched to foo(Object)
foo(null); // compilation problem -> "The method foo(String) is ambiguous"
}
public static void foo(String arg) { // More-specific
System.out.println("foo(String)");
}
public static void foo(Object arg) { // Generic
System.out.println("foo(Object)");
}
}
回答2:
Because the second commented out invocation with null is ambiguous to the compiler. The literal null could be a string or an object. Whereas the assigned value has a definite type. You need to cast the null, e.g. test.foo((String)null) to remove the ambiguity.
回答3:
Has anyone tried the example ???
With 1.6.0 foo(null) is dispatched to the most specific method applicable which is foo(String)...
If you add a new method say foo(Integer) the compiler cannot choose the most specific applicable method and shows an error.
-Patrick
回答4:
Sorry to use an answer, for a comment, but I need to post code that won't fit in comment.
@Yang, I am also able to compile and run the following. Can you post a complete code that compiles with one line commented such that if I uncomment that line it won't compile?
class NullType {
public static final void main(final String[] args) {
foo();
new Test().bar(new Test());
}
static void foo()
{
Object testVal = null;
foo(testVal); // dispatched to foo(Object)
// foo(null); // compilation problem -> "The method foo(String) is ambiguous"
}
public static void foo(String arg) { // More-specific
System.out.println("foo(String)");
}
public static void foo(Integer arg) { // More-specific
System.out.println("foo(Integer)");
}
public static void foo(Object arg) { // Generic
System.out.println("foo(Object)");
}
}
class Test
{
void bar(Test test)
{
Object testVal = null;
test.foo(testVal); // dispatched to foo(Object)
test.foo(null); // compilation problem -> "The method foo(String) is ambiguous"
}
public void foo(String arg) { // More-specific
System.out.println("foo(String)");
}
public void foo(Object arg) { // Generic
System.out.println("foo(Object)");
}
}
来源:https://stackoverflow.com/questions/377203/java-method-dispatch-with-null-argument