题目大意
略。
分析
先按着信封的宽度排序,宽度相等长度长的放前面,然后对长度做一次 LIS。
代码如下
1 #include <bits/stdc++.h>
2 using namespace std;
3
4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
5 #define Rep(i,n) for (int i = 0; i < (int)(n); ++i)
6 #define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i)
7 #define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i)
8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
12
13 #define pr(x) cout << #x << " = " << x << " "
14 #define prln(x) cout << #x << " = " << x << endl
15
16 #define LOWBIT(x) ((x)&(-x))
17
18 #define ALL(x) x.begin(),x.end()
19 #define INS(x) inserter(x,x.begin())
20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c
22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
24
25 #define ms0(a) memset(a,0,sizeof(a))
26 #define msI(a) memset(a,0x3f,sizeof(a))
27 #define msM(a) memset(a,-1,sizeof(a))
28
29 #define MP make_pair
30 #define PB push_back
31 #define ft first
32 #define sd second
33
34 template<typename T1, typename T2>
35 istream &operator>>(istream &in, pair<T1, T2> &p) {
36 in >> p.first >> p.second;
37 return in;
38 }
39
40 template<typename T>
41 istream &operator>>(istream &in, vector<T> &v) {
42 for (auto &x: v)
43 in >> x;
44 return in;
45 }
46
47 template<typename T>
48 ostream &operator<<(ostream &out, vector<T> &v) {
49 Rep(i, v.size()) out << v[i] << " \n"[i == v.size() - 1];
50 return out;
51 }
52
53 template<typename T1, typename T2>
54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
55 out << "[" << p.first << ", " << p.second << "]" << "\n";
56 return out;
57 }
58
59 inline int gc(){
60 static const int BUF = 1e7;
61 static char buf[BUF], *bg = buf + BUF, *ed = bg;
62
63 if(bg == ed) fread(bg = buf, 1, BUF, stdin);
64 return *bg++;
65 }
66
67 inline int ri(){
68 int x = 0, f = 1, c = gc();
69 for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
70 for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
71 return x*f;
72 }
73
74 template<class T>
75 inline string toString(T x) {
76 ostringstream sout;
77 sout << x;
78 return sout.str();
79 }
80
81 inline int toInt(string s) {
82 int v;
83 istringstream sin(s);
84 sin >> v;
85 return v;
86 }
87
88 //min <= aim <= max
89 template<typename T>
90 inline bool BETWEEN(const T aim, const T min, const T max) {
91 return min <= aim && aim <= max;
92 }
93
94 typedef unsigned int uI;
95 typedef long long LL;
96 typedef unsigned long long uLL;
97 typedef vector< int > VI;
98 typedef vector< bool > VB;
99 typedef vector< char > VC;
100 typedef vector< double > VD;
101 typedef vector< string > VS;
102 typedef vector< LL > VL;
103 typedef vector< VI > VVI;
104 typedef vector< VB > VVB;
105 typedef vector< VS > VVS;
106 typedef vector< VL > VVL;
107 typedef vector< VVI > VVVI;
108 typedef vector< VVL > VVVL;
109 typedef pair< int, int > PII;
110 typedef pair< LL, LL > PLL;
111 typedef pair< int, string > PIS;
112 typedef pair< string, int > PSI;
113 typedef pair< string, string > PSS;
114 typedef pair< double, double > PDD;
115 typedef vector< PII > VPII;
116 typedef vector< PLL > VPLL;
117 typedef vector< VPII > VVPII;
118 typedef vector< VPLL > VVPLL;
119 typedef vector< VS > VVS;
120 typedef map< int, int > MII;
121 typedef unordered_map< int, int > uMII;
122 typedef map< LL, LL > MLL;
123 typedef map< string, int > MSI;
124 typedef map< int, string > MIS;
125 typedef set< int > SI;
126 typedef stack< int > SKI;
127 typedef deque< int > DQI;
128 typedef queue< int > QI;
129 typedef priority_queue< int > PQIMax;
130 typedef priority_queue< int, VI, greater< int > > PQIMin;
131 const double EPS = 1e-8;
132 const LL inf = 0x7fffffff;
133 const LL infLL = 0x7fffffffffffffffLL;
134 const LL mod = 1e9 + 7;
135 const int maxN = 1e5 + 7;
136 const LL ONE = 1;
137 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
138 const LL oddBits = 0x5555555555555555;
139
140 struct Envelope{
141 int length, width;
142
143 inline bool operator< (const Envelope &x) const {
144 return width < x.width || width == x.width && length > x.length;
145 }
146 };
147
148 int N;
149 vector< Envelope > arr;
150 // dp[i] 表示以 arr[i].length 结尾的最长递增子序列
151 VI dp;
152 // smallEnds[i] 表示LIS长度为 i + 1 的最小结尾
153 VI smallEnds;
154
155 int LIS() {
156 dp.assign(N, 0);
157 smallEnds.clear();
158
159 Rep(i, N) {
160 auto it = lower_bound(ALL(smallEnds), arr[i].length);
161 dp[i] = it - smallEnds.begin() + 1;
162
163 if(it != smallEnds.end()) *it = arr[i].length;
164 else smallEnds.PB(arr[i].length);
165 }
166
167 return (int)smallEnds.size();
168 }
169
170 int main() {
171 //freopen("MyOutput.txt","w",stdout);
172 //freopen("input.txt","r",stdin);
173 //INIT();
174 scanf("%d", &N);
175 arr.resize(N);
176 Rep(i, N) scanf("%d%d", &arr[i].length, &arr[i].width);
177 sort(ALL(arr));
178 printf("%d\n", LIS());
179 return 0;
180 }
来源:oschina
链接:https://my.oschina.net/u/4270180/blog/3425794