问题
In Python 2.5, is there a way to create a decorator that decorates a class? Specifically, I want to use a decorator to add a member to a class and change the constructor to take a value for that member.
Looking for something like the following (which has a syntax error on \'class Foo:\':
def getId(self): return self.__id
class addID(original_class):
def __init__(self, id, *args, **kws):
self.__id = id
self.getId = getId
original_class.__init__(self, *args, **kws)
@addID
class Foo:
def __init__(self, value1):
self.value1 = value1
if __name__ == \'__main__\':
foo1 = Foo(5,1)
print foo1.value1, foo1.getId()
foo2 = Foo(15,2)
print foo2.value1, foo2.getId()
I guess what I\'m really after is a way to do something like a C# interface in Python. I need to switch my paradigm I suppose.
回答1:
I would second the notion that you may wish to consider a subclass instead of the approach you've outlined. However, not knowing your specific scenario, YMMV :-)
What you're thinking of is a metaclass. The __new__ function in a metaclass is passed the full proposed definition of the class, which it can then rewrite before the class is created. You can, at that time, sub out the constructor for a new one.
Example:
def substitute_init(self, id, *args, **kwargs):
pass
class FooMeta(type):
def __new__(cls, name, bases, attrs):
attrs['__init__'] = substitute_init
return super(FooMeta, cls).__new__(cls, name, bases, attrs)
class Foo(object):
__metaclass__ = FooMeta
def __init__(self, value1):
pass
Replacing the constructor is perhaps a bit dramatic, but the language does provide support for this kind of deep introspection and dynamic modification.
回答2:
Apart from the question whether class decorators are the right solution to your problem:
In Python 2.6 and higher, there are class decorators with the @-syntax, so you can write:
@addID
class Foo:
pass
In older versions, you can do it another way:
class Foo:
pass
Foo = addID(Foo)
Note however that this works the same as for function decorators, and that the decorator should return the new (or modified original) class, which is not what you're doing in the example. The addID decorator would look like this:
def addID(original_class):
orig_init = original_class.__init__
# Make copy of original __init__, so we can call it without recursion
def __init__(self, id, *args, **kws):
self.__id = id
self.getId = getId
orig_init(self, *args, **kws) # Call the original __init__
original_class.__init__ = __init__ # Set the class' __init__ to the new one
return original_class
You could then use the appropriate syntax for your Python version as described above.
But I agree with others that inheritance is better suited if you want to override __init__.
回答3:
No one has explained that you can dynamically define classes. So you can have a decorator that defines (and returns) a subclass:
def addId(cls):
class AddId(cls):
def __init__(self, id, *args, **kargs):
super(AddId, self).__init__(*args, **kargs)
self.__id = id
def getId(self):
return self.__id
return AddId
Which can be used in Python 2 (the comment from Blckknght which explains why you should continue to do this in 2.6+) like this:
class Foo:
pass
FooId = addId(Foo)
And in Python 3 like this (but be careful to use super() in your classes):
@addId
class Foo:
pass
So you can have your cake and eat it - inheritance and decorators!
回答4:
That's not a good practice and there is no mechanism to do that because of that. The right way to accomplish what you want is inheritance.
Take a look into the class documentation.
A little example:
class Employee(object):
def __init__(self, age, sex, siblings=0):
self.age = age
self.sex = sex
self.siblings = siblings
def born_on(self):
today = datetime.date.today()
return today - datetime.timedelta(days=self.age*365)
class Boss(Employee):
def __init__(self, age, sex, siblings=0, bonus=0):
self.bonus = bonus
Employee.__init__(self, age, sex, siblings)
This way Boss has everything Employee has, with also his own __init__ method and own members.
回答5:
There's actually a pretty good implementation of a class decorator here:
https://github.com/agiliq/Django-parsley/blob/master/parsley/decorators.py
I actually think this is a pretty interesting implementation. Because it subclasses the class it decorates, it will behave exactly like this class in things like isinstance checks.
It has an added benefit: it's not uncommon for the __init__ statement in a custom django Form to make modifications or additions to self.fields so it's better for changes to self.fields to happen after all of __init__ has run for the class in question.
Very clever.
However, in your class you actually want the decoration to alter the constructor, which I don't think is a good use case for a class decorator.
回答6:
I'd agree inheritance is a better fit for the problem posed.
I found this question really handy though on decorating classes, thanks all.
Here's another couple of examples, based on other answers, including how inheritance affects things in Python 2.7, (and @wraps, which maintains the original function's docstring, etc.):
def dec(klass):
old_foo = klass.foo
@wraps(klass.foo)
def decorated_foo(self, *args ,**kwargs):
print('@decorator pre %s' % msg)
old_foo(self, *args, **kwargs)
print('@decorator post %s' % msg)
klass.foo = decorated_foo
return klass
@dec # No parentheses
class Foo...
Often you want to add parameters to your decorator:
from functools import wraps
def dec(msg='default'):
def decorator(klass):
old_foo = klass.foo
@wraps(klass.foo)
def decorated_foo(self, *args ,**kwargs):
print('@decorator pre %s' % msg)
old_foo(self, *args, **kwargs)
print('@decorator post %s' % msg)
klass.foo = decorated_foo
return klass
return decorator
@dec('foo decorator') # You must add parentheses now, even if they're empty
class Foo(object):
def foo(self, *args, **kwargs):
print('foo.foo()')
@dec('subfoo decorator')
class SubFoo(Foo):
def foo(self, *args, **kwargs):
print('subfoo.foo() pre')
super(SubFoo, self).foo(*args, **kwargs)
print('subfoo.foo() post')
@dec('subsubfoo decorator')
class SubSubFoo(SubFoo):
def foo(self, *args, **kwargs):
print('subsubfoo.foo() pre')
super(SubSubFoo, self).foo(*args, **kwargs)
print('subsubfoo.foo() post')
SubSubFoo().foo()
Outputs:
@decorator pre subsubfoo decorator
subsubfoo.foo() pre
@decorator pre subfoo decorator
subfoo.foo() pre
@decorator pre foo decorator
foo.foo()
@decorator post foo decorator
subfoo.foo() post
@decorator post subfoo decorator
subsubfoo.foo() post
@decorator post subsubfoo decorator
I've used a function decorator, as I find them more concise. Here's a class to decorate a class:
class Dec(object):
def __init__(self, msg):
self.msg = msg
def __call__(self, klass):
old_foo = klass.foo
msg = self.msg
def decorated_foo(self, *args, **kwargs):
print('@decorator pre %s' % msg)
old_foo(self, *args, **kwargs)
print('@decorator post %s' % msg)
klass.foo = decorated_foo
return klass
A more robust version that checks for those parentheses, and works if the methods don't exist on the decorated class:
from inspect import isclass
def decorate_if(condition, decorator):
return decorator if condition else lambda x: x
def dec(msg):
# Only use if your decorator's first parameter is never a class
assert not isclass(msg)
def decorator(klass):
old_foo = getattr(klass, 'foo', None)
@decorate_if(old_foo, wraps(klass.foo))
def decorated_foo(self, *args ,**kwargs):
print('@decorator pre %s' % msg)
if callable(old_foo):
old_foo(self, *args, **kwargs)
print('@decorator post %s' % msg)
klass.foo = decorated_foo
return klass
return decorator
The assert checks that the decorator has not been used without parentheses. If it has, then the class being decorated is passed to the msg parameter of the decorator, which raises an AssertionError.
@decorate_if only applies the decorator if condition evaluates to True.
The getattr, callable test, and @decorate_if are used so that the decorator doesn't break if the foo() method doesn't exist on the class being decorated.
来源：https://stackoverflow.com/questions/681953/how-to-decorate-a-class