python-2.5

问题 Ok, so I am making a video. I want to know exactly how to use the FPS argument. It is a float, so I assumed it was what interval do I want between each frame. Can you give an example? I just want to know how the video would change with varying FPS argument values., because my video I made is way too fast now. Thanks! 回答1: It really is just that - frames per second . In other words, how many frames do you want to display every second? Here is an example: writer = cv2.VideoWriter(filename="my

问题 I encountered Error: 'module' object has no attribute 'copy' while running a pygame program. In my code, I never referred to a copy attribute, so I don't understand where the error is coming from. 回答1: I think there is a python file named "copy" in your directory. I had the same problem, after I delete the "copy" file, the error has gone. 来源： https://stackoverflow.com/questions/23418949/pygame-attributeerror-module-object-has-no-attribute-copy

问题 I have this installed on Windows 7 Python 2.7.6 (my default, with virtualenv installed) Python 2.4.4 Python 2.5.4 Python 2.6.6 Python 3.3.3 virtualenv 1.10.1 I want to test code on all of those python installations. (Similar quesion Multiple python versions using virtualenv -p (and virtualenvwrapper-win) on Windows does not answer this.) This is what I tried so far: Python 2.4 gives a syntax error (creates an environment but with PY27 installed!): >virtualenv -p c:\apps\Python24\python.exe

问题 I have this installed on Windows 7 Python 2.7.6 (my default, with virtualenv installed) Python 2.4.4 Python 2.5.4 Python 2.6.6 Python 3.3.3 virtualenv 1.10.1 I want to test code on all of those python installations. (Similar quesion Multiple python versions using virtualenv -p (and virtualenvwrapper-win) on Windows does not answer this.) This is what I tried so far: Python 2.4 gives a syntax error (creates an environment but with PY27 installed!): >virtualenv -p c:\apps\Python24\python.exe

问题 I need install cx_Oracle for Python 2.5 on Linux (Linux 2.6.18-371.1.2.el5 i686). I have installed Oracle client 10.2.0.4. I have tried following: 1. Download cx_Oracle tar.gz from http://sourceforge.net/projects/cx-oracle/files/ . I don't know which of listed version are suitable for python 2.5 and Oracle client 10.2.0.4, so try cx_Oracle-5.1.tar.gz. Unpacked tar, go to unpacked folder and run python setup.py install. I got error: Traceback (most recent call last): File "setup.py", line 187,

问题 Can I use clean Python 3 super() syntax in Python 2.5.6? Maybe with some kind of __future__ import? 回答1: You cannot use a bare super() call that contains no type/class. Nor can you implement a replacement for it that will work. Python 3.x contains special support to enable bare super() calls (it places a __class__ cell variable in all functions defined within a class - see PEP 3135 Update As of Python 2.6+, bare super() calls can be used via the future Python package. See posita's answer for

问题 After somes problems with a simple import of httplib2 (see my post here), i meet a different problem with the import of gflags. In fact, on dev server, i have an ImportError the first time that I lanch the apps. But, if i refresh the browser, the apps works ! If i looking in logs, i can see : ... ImportError: No module named gflags [App Instance] [0] [dev_appserver.py:2891] INFO "GET / HTTP/1.1" 500 - [App Instance] [0] [py_zipimport.py:148] INFO zipimporter('/usr/lib/python2.5/site-packages

问题 Is it possible to access the 'owner' class inside a descriptor during the __init__ function of that descriptor, without passing it in manually as in this example? class FooDescriptor(object): def __init__(self, owner): #do things to owner here setattr(owner, 'bar_attribute', 'bar_value') class BarClass(object): foo_attribute = FooDescriptor(owner=BarClass) 回答1: One way to do something like that is with a metaclass. Just make sure it's really what you want, and don't just copy blindly if you

问题 I want to extract a file from a zip to a specific path, ignoring the file path in the archive. This is very easy in Python 2.6 (my docstring is longer than the code) import shutil import zipfile def extract_from_zip(name, dest_path, zip_file): """Similar to zipfile.ZipFile.extract but extracts the file given by name from the zip_file (instance of zipfile.ZipFile) to the given dest_path *ignoring* the filename path given in the archive completely instead of preserving it as extract does. """

问题 I want to extract a file from a zip to a specific path, ignoring the file path in the archive. This is very easy in Python 2.6 (my docstring is longer than the code) import shutil import zipfile def extract_from_zip(name, dest_path, zip_file): """Similar to zipfile.ZipFile.extract but extracts the file given by name from the zip_file (instance of zipfile.ZipFile) to the given dest_path *ignoring* the filename path given in the archive completely instead of preserving it as extract does. """