Celery stop execution of a chain

坚强是说给别人听的谎言 提交于 2019-11-27 11:49:58

问题


I have a check_orders task that's executed periodically. It makes a group of tasks so that I can time how long executing the tasks took, and perform something when they're all done (this is the purpose of res.join [1] and grouped_subs) The tasks that are grouped are pairs of chained tasks.

What I want is for when the first task doesn't meet a condition (fails) don't execute the second task in the chain. I can't figure this out for the life of me and I feel this is pretty basic functionality for a job queue manager. When I try the things I have commented out after [2] (raising exceptions, removing callbacks)... we get stuck on the join() in check_orders for some reason (it breaks the group). I've tried setting ignore_result to False as well for all these tasks but it still doesn't work.

@task(ignore_result=True)
def check_orders():
    # check all the orders and send out appropriate notifications
    grouped_subs = []

    for thingy in things:
       ...

        grouped_subs.append(chain(is_room_open.subtask((args_sub_1, )), 
                        notify.subtask((args_sub_2, ), immutable=True)))

    res = group(grouped_subs).apply_async()

    res.join()         #[1]
    logger.info('Done checking orders at %s' % current_task.request.id))

@task(ignore_result=True)
def is_room_open(args_sub_1):
    #something time consuming
    if http_req_and_parse(args_sub_1):
        # go on and do the notify task
        return True
    else:
        # [2]
        # STOP THE CHAIN SOMEHOW! Don't execute the rest of the chain, how?
        # None of the following things work:
        # is_room_open.update_state(state='FAILURE')
        # raise celery.exceptions.Ignore()
        # raise Exception('spam', 'eggs')
        # current_task.request.callbacks[:] = []

@task(ignore_result=True)
def notify(args_sub_2):
    # something else time consuming, only do this if the first part of the chain 
    # passed a test (the chained tasks before this were 'successful'
    notify_user(args_sub_2)

回答1:


In my opinion this is a common use-case that doesn't get enough love in the documentation.

Assuming you want to abort a chain mid-way while still reporting SUCCESS as status of the completed tasks, and not sending any error log or whatnot (else you can just raise an exception) then a way to accomplish this is:

@app.task(bind=True)  # Note that we need bind=True for self to work
def task1(self, other_args):
    #do_stuff
    if end_chain:
        self.request.callbacks = None
        return
    #Other stuff to do if end_chain is False

So in your example:

@app.task(ignore_result=True, bind=True)
def is_room_open(self, args_sub_1):
    #something time consuming
    if http_req_and_parse(args_sub_1):
        # go on and do the notify task
        return True
    else:
        self.request.callbacks = None

Will work. Note that instead of ignore_result=True and subtask() you can use the shortcut .si() as stated by @abbasov-alexander

Edited to work with EAGER mode, as suggested by @PhilipGarnero in the comments.




回答2:


It's unbelievable as a so common case isn't treated in any official documentation. I had to cope with the same issue (but using shared_tasks with bind option, so we have visibility of self object), so I wrote a custom decorator that handles automatically the revocation:

def revoke_chain_authority(a_shared_task):
    """
    @see: https://gist.github.com/bloudermilk/2173940
    @param a_shared_task: a @shared_task(bind=True) celery function.
    @return:
    """
    @wraps(a_shared_task)
    def inner(self, *args, **kwargs):
        try:
            return a_shared_task(self, *args, **kwargs)
        except RevokeChainRequested, e:
            # Drop subsequent tasks in chain (if not EAGER mode)
            if self.request.callbacks:
                self.request.callbacks[:] = []
            return e.return_value

    return inner

You can use it as follows:

@shared_task(bind=True)
@revoke_chain_authority
def apply_fetching_decision(self, latitude, longitude):
    #...

    if condition:
        raise RevokeChainRequested(False)

See the full explanation here. Hope it helps!




回答3:


Firstly, it seems if into the function exists exception ignore_result don't help you.

Secondly, you use immutable=True It means that next function (in our case is notify) does not take additional arguments. You should use notify.subtask((args_sub_2, ), immutable=False) of course if it suitable for your decision.

Third, you can use shortcuts:

notify.si(args_sub_2) instead notify.subtask((args_sub_2, ), immutable=True)

and

is_room_open.s(args_sub_1) instead is_room_open.subtask((args_sub_1, ))

Try use it code:

@task
def check_orders():
    # check all the orders and send out appropriate notifications
    grouped_subs = []

    for thingy in things:
       ...

        grouped_subs.append(chain(is_room_open.s(args_sub_1), 
                                  notify.s(args_sub_2)))

    res = group(grouped_subs).apply_async()

    res.join()         #[1]
    logger.info('Done checking orders at %s' % current_task.request.id))

@task
def is_room_open(args_sub_1):
    #something time consuming
    if http_req_and_parse(args_sub_1):
        # go on and do the notify task
        return True
    else:
        # [2]
        # STOP THE CHAIN SOMEHOW! Don't execute the rest of the chain, how?
        # None of the following things work:
        # is_room_open.update_state(state='FAILURE')
        # raise celery.exceptions.Ignore()
        # raise Exception('spam', 'eggs')
        # current_task.request.callbacks[:] = []
        return False

@task
def notify(result, args_sub_2):
    if result:
        # something else time consuming, only do this if the first part of the chain 
        # passed a test (the chained tasks before this were 'successful'
        notify_user(args_sub_2)
        return True
    return False

If you want catch exceptions you must use callback as so

is_room_open.s(args_sub_1, link_error=log_error.s())

from proj.celery import celery

@celery.task
def log_error(task_id):
    result = celery.AsyncResult(task_id)
    result.get(propagate=False)  # make sure result written.
    with open(os.path.join('/var/errors', task_id), 'a') as fh:
        fh.write('--\n\n%s %s %s' % (
            task_id, result.result, result.traceback))


来源:https://stackoverflow.com/questions/17461374/celery-stop-execution-of-a-chain

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