How to use a 'subroutine reference' as a hash key

。_饼干妹妹 提交于 2020-01-04 16:57:11

问题


In Perl, I'm learning how to dereference 'subroutine references'. But I can't seem to use a subroutine reference as a hash 'key'.

In the following sample code,

  1. I can create a reference to a subroutine ($subref) and then dereference it to run the subroutine (&$subref)
  2. I can use the reference as a hash 'value' and then easily dereference that
  3. But I cannot figure out how to use the reference as a hash 'key'. When I pull the key out of the hash, Perl interprets the key as a string value (not a reference) - which I now understand (thanks to this site!). So I've tried Hash::MultiKey, but that seems to turn it into an array reference. I want to treat it as a subroutine/code reference, assuming this is somehow possible?

Any other ideas?

use strict;
#use diagnostics;
use Hash::MultiKey;    

my $subref = \&hello;

#1: 
&$subref('bob','sue');               #okay

#2:
my %hash;
$hash{'sayhi'}=$subref;
&{$hash{'sayhi'}}('bob','sue');      #okay

#3: 
my %hash2;
tie %hash2, 'Hash::MultiKey';
$hash2{$subref}=1;
foreach my $key (keys %hash2) {
  print "Ref type is: ". ref($key)."\n";
  &{$key}('bob','sue');              # Not okay 
}

sub hello {
    my $name=shift;
    my $name2=shift;
    print "hello $name and $name2\n";
}

This is what is returned:

hello bob and sue
hello bob and sue
Ref type is: ARRAY
Not a CODE reference at d:\temp\test.pl line 21.

回答1:


That is correct, a normal hash key is only a string. Things that are not strings get coerced to their string representation.

my $coderef = sub { my ($name, $name2) = @_; say "hello $name and $name2"; };
my %hash2 = ( $coderef => 1, );
print keys %hash2;  # 'CODE(0x8d2280)'

Tieing is the usual means to modify that behaviour, but Hash::MultiKey does not help you, it has a different purpose: as the name says, you may have multiple keys, but again only simple strings:

use Hash::MultiKey qw();
tie my %hash2, 'Hash::MultiKey';
$hash2{ [$coderef] } = 1;
foreach my $key (keys %hash2) {
    say 'Ref of the key is: ' . ref($key);
    say 'Ref of the list elements produced by array-dereferencing the key are:';
    say ref($_) for @{ $key }; # no output, i.e. simple strings
    say 'List elements produced by array-dereferencing the key are:';
    say $_ for @{ $key }; # 'CODE(0x8d27f0)'
}

Instead, use Tie::RefHash. (Code critique: prefer this syntax with the -> arrow for dereferencing a coderef.)

use 5.010;
use strict;
use warnings FATAL => 'all';
use Tie::RefHash qw();

my $coderef = sub {
    my ($name, $name2) = @_;
    say "hello $name and $name2";
};

$coderef->(qw(bob sue));

my %hash = (sayhi => $coderef);
$hash{sayhi}->(qw(bob sue));

tie my %hash2, 'Tie::RefHash';
%hash2 = ($coderef => 1);
foreach my $key (keys %hash2) {
    say 'Ref of the key is: ' . ref($key);   # 'CODE'
    $key->(qw(bob sue));
}



回答2:


From perlfaq4:

How can I use a reference as a hash key?

(contributed by brian d foy and Ben Morrow)

Hash keys are strings, so you can't really use a reference as the key. When you try to do that, perl turns the reference into its stringified form (for instance, HASH(0xDEADBEEF) ). From there you can't get back the reference from the stringified form, at least without doing some extra work on your own.

Remember that the entry in the hash will still be there even if the referenced variable goes out of scope, and that it is entirely possible for Perl to subsequently allocate a different variable at the same address. This will mean a new variable might accidentally be associated with the value for an old.

If you have Perl 5.10 or later, and you just want to store a value against the reference for lookup later, you can use the core Hash::Util::Fieldhash module. This will also handle renaming the keys if you use multiple threads (which causes all variables to be reallocated at new addresses, changing their stringification), and garbage-collecting the entries when the referenced variable goes out of scope.

If you actually need to be able to get a real reference back from each hash entry, you can use the Tie::RefHash module, which does the required work for you.

So it looks like Tie::RefHash will do what you want. But to be honest, I don't think that what you want to do is a particularly good idea.




回答3:


Why do you need it? If you e.g. need to store parameters to the functions in the hash, you can use HoH:

my %hash;
$hash{$subref} = { sub => $subref,
                   arg => [qw/bob sue/],
                 };
foreach my $key (keys %hash) {
    print "$key: ref type is: " . ref($key) . "\n";
    $hash{$key}{sub}->( @{ $hash{$key}{arg} } );
}

But then, you can probably choose a better key anyway.



来源:https://stackoverflow.com/questions/10795386/how-to-use-a-subroutine-reference-as-a-hash-key

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!