问题
Hi I am new to for xml
I have a query like this
SELECT ProjectId,
ProjectCode,
ProjectName,
TechId,
-- LocationId,
( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location') ),
RtoId,
CreatedBy,
CreatedOn,
LastUpdatedBy,
LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
it return the xml as
<ProjectInfo>
<ProjectId>1</ProjectId>
<ProjectCode>US-W1-00001</ProjectCode>
<ProjectName>Rees</ProjectName>
<TechId>1</TechId>
<Location><GeoId>235</GeoId><PoliticalDivisionId>2</PoliticalDivisionId><GeographicLocationName>UNITED STATES</GeographicLocationName><IsoCode>US</IsoCode></Location>
<RtoId>3</RtoId>
<CreatedBy>1</CreatedBy>
<CreatedOn>2013-06-30T20:55:21.587</CreatedOn>
<LastUpdatedBy>1</LastUpdatedBy>
<LastUpdatedOn>2013-06-30T20:55:21.587</LastUpdatedOn>
prject tags are shown in the form < and > . But inner tags of Location are shown as “<” and “>” how do I replace them with < and >
Update : there was a small error in the question . inner xml was not for rtoid , it was for Location
I updated query as
SELECT ProjectId,
ProjectCode,
ProjectName,
TechId,
-- LocationId,
replace(replace( ( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location') ), '<', '<'), '>', '>'),
RtoId,
CreatedBy,
CreatedOn,
LastUpdatedBy,
LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
but still its the same
回答1:
I think correct way is using TYPE Directive
SELECT ProjectId,
...,
( SELECT Geo, ...
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location'), TYPE),
RtoId, ^^^^
...
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
回答2:
The way that I've found is with explicitly replacing them:
select ProjectId, ProjectCode, ProjectName, TechId,
replace(replace(RtoId, '<', '<'), '>', '>') as RtoId,
. . .
from (<your query here>)
回答3:
SELECT ProjectId,
ProjectCode,
ProjectName,
TechId,
-- LocationId,
replace(replace(( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location') ), '<', '<'), '>', '>')
RtoId,
CreatedBy,
CreatedOn,
LastUpdatedBy,
LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
回答4:
format the data into xml, use cast(@xml as xml).
回答5:
Please try:
(SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,
Longitude,Latitude,ParentLocationId,
t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location'), type
).value('(./text())[1]','varchar(max)')
回答6:
SELECT ProjectId,
ProjectCode,
ProjectName,
TechId,
-- LocationId,
cast(( SELECT GeoId,PoliticalDivisionId ,GeographicLocationName,IsoCode,Longitude,Latitude,ParentLocationId,
t2.CreatedBy,t2.CreatedOn,t2.LastUpdatedBy,t2.LastUpdatedOn
FROM GeographicLocation t2
WHERE GeoId = t1.LocationId
FOR XML PATH('Location') ) as xml),
RtoId,
CreatedBy,
CreatedOn,
LastUpdatedBy,
LastUpdatedOn
FROM Project t1
where ProjectId=1
FOR XML PATH('ProjectInfo')
来源:https://stackoverflow.com/questions/17503725/replace-lt-and-gt-with-and-in-sql-server