问题
I am writing a regular expression to extract a pattern of numbers from a string. When I used to run the below code snippet, it is showing a warning
"preg_match() [<a href='function.preg-match'>function.preg-match</a>]: No ending delimiter '^' "
Could any one tell me why this warning and how to fix it?
$temp=0;
$exp=(explode(" ",$message1));
while($temp<sizeof($exp))
{
if(preg_match("^(+91|0091|0)?[7-9][0-9]{9}$",$exp[$temp]))
{
$pat=$exp[$temp];
}
}
回答1:
You forgot the regex delimiter, use this instead (inserted / at the very beginning and end of the regex):
if(preg_match('/^(+91|0091|0)?[7-9][0-9]{9}$/', $exp[$temp]))
The reason for the error you got is that PHP allows any delimiter character. In your case it used ^ since that's the first character in your string. However, that obviously didn't work since it never found another caret to end the regex. Using ^ would be a bad idea anyway since it has a meaning in the regex itself.
来源：https://stackoverflow.com/questions/11334591/why-does-this-regular-expression-result-in-preg-match-no-ending-delimite