Using dustjs how do I show a block of code when an array's size is greater than one

随声附和 提交于 2019-12-24 06:44:13

问题


I am using dust 1.1.1. I've tried nesting the @size help inside of an @if but that broke.

Another trick to it is once I've determined the length is greater than one I then want to iterate through the array.


回答1:


The Dust grammar does not allow a helper to be used inside another helper, except in the body.

Instead, I would try something like this:

{#myArray}
  {@gt key=$len value=1}{.}{/gt}
{/myArray}

This will only output the value of the element in the array if the length of the array ($len) is greater than 1.




回答2:


My workaround for this was:

{?myArray[1]}
    {!Do greater than one stuff!}
{/myArray[1]}


来源:https://stackoverflow.com/questions/17220800/using-dustjs-how-do-i-show-a-block-of-code-when-an-arrays-size-is-greater-than

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