问题
How do I perform a mod operation between two integers in C++?
回答1:
Like this: x=y%z
回答2:
In c++, use % operator
More Help
回答3:
As the other answers have stated, you can use the C++ % operator. But be aware that there's a wrinkle no one has mentioned yet: in the expression a % b
, what if a
is negative?
Should the result of this operation be positive or negative? The C++ standard leaves this up to the
implementation. So if you want to handle negative inputs portably, you should probably
do something like r = abs(a) % b
, then fix up the sign of r
to match your requirements.
回答4:
C++ has the %
operator, occasionally and misleadingly named "the modulus" operator. In particular the STL has the modulus<>
functor in the <functional>
header. That's not the mathematical modulus operator, mind you, because in modulus arithmetics a mod b
by definition evaluates to a non-negative value for any value of a
and any positive value of b
. In C++ the sign of the result of a % b
is implementation-defined if either of the arguments is negative. So, we would more appropriately name the %
operator the remainder operator.
That said, if you truly want the mathematical modulus operator then you can define a function to do just that:
template<typename V>
V mod(const V& a, const V& b)
{
return (a % b + b) % b;
}
So long as b
is a positive value a call to the above function will yield a non-negative result.
回答5:
Using the modulus %
operator :
int modulus_a_b = a % b;
回答6:
if you use double variable, you should use;
double x;
double y;
double result = fmod(x, y);
来源:https://stackoverflow.com/questions/2581594/how-do-i-do-modulus-in-c