问题
I'm confused by something I just ran into in a script I was working on. I had the following:
function getPart($part)
{
$array = array('a', 'b', 'c');
if ($part == 'first') $part = 0;
if ($part == 'last') $part = count($array) - 1;
if (isset($array[$part])) return $array[$part];
return false;
}
$position = 0;
echo getPart($position);
So, if I were to try the string "first", I should get "a" as the output. With the string "last" I should get "c" and so on. When I run the script above, with PHP 5.3, I get "c" ...
Confused, I ran a quick test ...
var_dump(0 == 'first');
var_dump(0 == 'last');
Both return TRUE
... WHY??? I am so confused by this behavior!
回答1:
If you try to compare a string to a number, PHP will try to convert the string to a number. In this case, it fails to do so, since PHP can't convert "first" or "last" into a number, so it simply converts it to zero. This makes the check 0 == 0
, which is, of course, true. Use the identity operator, ===
, if you want PHP to not attempt to convert anything (so, the two operands must have the same value and be of the same type).
回答2:
Check out (int) 'first'
. That is essentially what PHP is doing to the right hand operand.
PHP will coerce operand types when not using the strict equality comparison operator (===
) between two operands of different types.
回答3:
PHP is weakly typed. What's happening there is it's trying to convert "first"
to a number. It fails, and returns zero. It now has two numbers: zero and zero. To make it not try to convert the types, use ===
rather than ==
.
回答4:
PHP is a bit strange in that it treats a string in numeric comparison as 0. You can force string comparison by quoting the variables:
function getPart($part)
{
$array = array('a', 'b', 'c');
if ("$part" == 'first') $part = 0;
if ("$part" == 'last') $part = count($array) - 1;
if (isset($array[$part])) return $array[$part];
return false;
}
来源:https://stackoverflow.com/questions/6644911/in-php-0-int-zero-is-equal-to-first-or-last-strings