问题
I am not a novice user of R, but the following is most confusing.
I have a data frame (although the problem is equally present for matrices) of categorical variables taking the values +1/-1, which I'd like to convert into factors.
mat <- matrix(sample(c(-1, +1), 16, replace = T), nrow = 4)
mat <- data.frame(mat)
However, using
mat <- apply(mat, 2, factor)
turns integers into characters instead of factors:
> mat
[,1] [,2] [,3] [,4]
[1,] "-1" "1" "-1" "1"
[2,] "-1" "-1" "-1" "-1"
[3,] "-1" "1" "1" "1"
[4,] "-1" "-1" "1" "1"
Perhaps in the same vein (and I had a problem of this sort with some of my other data) trying to convert character names in matrices and data frames into factors results in more confusing behaviour:
mat2 <- matrix(sample(letters, 16, replace = T), nrow = 4)
> mat2
[,1] [,2] [,3] [,4]
[1,] "x" "m" "r" "e"
[2,] "u" "r" "b" "p"
[3,] "j" "p" "h" "j"
[4,] "k" "s" "e" "x"
mat2[,1] <- factor(mat2[,1])
> mat2
[,1] [,2] [,3] [,4]
[1,] "4" "m" "r" "e"
[2,] "3" "r" "b" "p"
[3,] "1" "p" "h" "j"
[4,] "2" "s" "e" "x"
any help or clarification would be appreciated.
回答1:
Always remember that data frames are lists, and so operating on columns is just like iterating over elements of a list. I think maybe you intended to do something more like this:
mat[] <- lapply(mat,factor)
or this:
as.data.frame(lapply(mat,factor))
Although even here, note that the levels of each factor are not the same!
来源:https://stackoverflow.com/questions/16990437/unexpected-conversion-to-chars-instead-of-factors-in-data-frames-and-matrices