ampl display variable depending on a condition

问题

suppose we have the following ampl model:

set objects;
set sacks;
...
var Take{objects, sacks} binary;
...
display Take;

after solving the optimization problem I want to display only the lines of Take that equal 1

回答1:

You can do something like this:

for{o in objects, s in sacks: Take[o,s] = 1} {
    printf "\n %s %s", o,s; 
}

来源：https://stackoverflow.com/questions/49281515/ampl-display-variable-depending-on-a-condition