Update: gutted the question with a simpler example, that isn't answered by the originally accepted answer
Given the following class, and its ancestor:
TComputer = class(TObject)
public
constructor Create(Teapot: string='');
end;
TCellPhone = class(TComputer)
public
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
Right now TCellPhone
has 3 constructors visible:
- Cup: Integer
- Cup: Integer; Teapot: string
- Teapot: string = ''
What do i do to TCellPhone
so that the ancestor constructor (Teapot: string = ''
) is not visible, leaving only the declared constructors:
- Cup: Integer
- Cup: Integer; Teapot: string
Note: Usually the simple act of having a descendant constructor hides the ancestor:
TCellPhone = class(TComputer) public constructor Create(Cup: Integer); virtual; end;
- Cup: Integer
And if you wanted to keep both the ancestor constructor and the descendant, you would mark the descendant as an
overload
:TCellPhone = class(TComputer) public constructor Create(Cup: Integer); overload; virtual; end;
- Cup: Integer
- Teapot: string = ''
In this question's example code, Delphi is mistaking my overload
keywords:
TCellPhone = class(TComputer)
public
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
to think that:
- i want to overload my constructors with the ancestor,
- when really i want to overload it with the sibling
How do i hide the ancestor constructor?
Note: It might be impossible to hide the ancestor, non-virtual, constructor using the Delphi language as it is currently defined. "Not possible" is a valid answer.
Attempted Answer (failed)
i tried marking the descendant constructors with reintroduce
(falling back to my mode of randomly adding keywords until it works):
TCellPhone = class(TComputer)
public
constructor Create(Cup: Integer); reintroduce; overload; virtual;
constructor Create(Cup: Integer; Teapot: string); reintroduce; overload; virtual;
end;
But that didn't work, all three constructors are still visible. :(
Original Question
i have an object that descends from a class that has constructors don't want to see:
TEniac = class(TObject)
constructor Create(PowerCord: TPowerCord=nil); //calls inherited Create
TComputer = class(TEniac) ...
constructor Create(PowerCord: TPowerCord=nil); //calls inherited Create(nil)
TCellPhone = class(TComputer)
constructor Create(sim: TSimChip; UnlockCode: Integer); //calls inherited Create(nil)
TiPhone = class(TCellPhone)
constructor Create(sim: TSimChip); //calls inherited Create(sim, 0)
Note: This is a hypothetical example. As in the real world, the ancestor objects cannot be changed without breaking existing code.
Now when someone's using TiPhone
i don't want them even being able to see the constructor from TEniac
:
iphone := TiPhone.Create(powerCord);
Worse still: if they call that constructor, they completely miss my constructor, and everything done in between. It's pretty easy to call the wrong constructor, all of them are visible in the IDE code-completion, and will compile:
TiPhone.Create;
and they get a completely invalid object.
i could change TCellPhone
to throw an exception in those constructors:
TCellPhone.Create(PowerCord: TPowercord)
begin
raise Exception.Create('Don''t use.');
end;
But developers won't realize they're calling the wrong constructor until the customer finds the error one day and fines us bazillions of dollars. In fact, i'm trying to find everywhere i call the wrong constructor - but i can't figure out how to make Delphi tell me!
It's impossible to ever make a constructors introduced in an ancestor inaccessible for the creation of a derived class in Delphi because you can always do this:
type
TComputerClass = class of TComputer;
var
CellPhoneClass: TComputerClass = TCellPhone;
CellPhone : TCellPhone;
begin
CellPhone := CellPhoneClass.Create('FUBAR') as TCellPhone;
end;
Nothing you could do in the code of any derived class would ever be able to prevent anyone from calling the TComputer.Create constructor for creating an instance of the derived class.
The best you could do is:
TComputer = class(TObject)
public
constructor Create(Teapot: string=''); virtual;
end;
TCellPhone = class(TComputer)
public
constructor Create(Teapot: string=''); overload; override;
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
In that case the code above would at least be calling TCellPhone.Create(Teapot: string='')
instead of TComputer.Create(Teapot: string='')
If I remember correctly, then reintroduce
should help for virtual methods.
The reintroduce directive suppresses compiler warnings about hiding previously declared virtual methods. Use reintroduce when you want to hide an inherited virtual method with a new one.
To answer your updated question - I think it's not possbile to hide a non-virtual constructor with overloading in a directly derived class, but I tried the following successfully:
TComputer = class(TObject)
public
constructor Create(Teapot: string='');
end;
TIndermediateComputer = class(TComputer)
protected
// hide the constructor
constructor Create;
end;
TCellPhone = class(TIndermediateComputer)
public
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
You can't hide the parent class' constructor unless it was declared virtual or dynamic. You can however prevent it from being called from the child class. Consider your example:
TComputer = class(TObject)
public
constructor Create(Teapot: string='');
end;
TCellPhone = class(TComputer)
public
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
TComputer.Create
will always be visible from TCellPhone
. You can prevent TComputer.Create
from being inadvertantly called by declaring a TCellPhone.Create
with the same signature.
TCellPhone = class(TComputer)
public
constructor Create(Teapot: string='');
constructor Create(Cup: Integer); overload; virtual;
constructor Create(Cup: Integer; Teapot: string); overload; virtual;
end;
Then as long as you don't have a call to inherited
in the body of TCellPhone.Create(Teapot: string='')
you can prevent TComputer.Create
from being called in TCellPhone
and its descendants. The following:
TCellphone.Create;
TCellphone.Create('MyPhone');
Will resolve to TCellPhone's implementation.
Additionally:
TiPhone = class(TCellPhone)
constructor Create;
end;
constructor TiPhone.Create;
begin
inherited;
end;
Will invoke TCellPhone.Create
and not TComputer.Create
.
Instead of only raising an "Don't use" exception in the overridden invalid constructors, consider marking them deprecated in the class where they become invalid. That should produce nice compiler warnings when these invalid constructors are used erroneosly.
TCellPhone = class(TComputer)
constructor Create(PowerCord: TPowerCord=nil); deprecated;
constructor Create(sim: TSimChip; UnlockCode: Integer); //calls inherited Create(nil)
In addition, use override or reintroduce as needed.
You want to reintroduce the constructor:
TiPhone = class(TCellPhone)
constructor Create(sim: TSimChip); reintroduce;
See TComponent.Create
in the Delphi source code for a real-world example of this.
I know that this is 5 years old topic, but still it may help someone. The only way to hide the ancestor's constructor is to rename one of the two Create methods to something else and remove the need of overload directive. It looks weird but it's the only way. At least in older versions of Delphi. I don't know is it possible now in the XE xxx versions.
来源:https://stackoverflow.com/questions/3874330/delphi-how-to-hide-ancestor-constructors