问题
How to call the Ajax ready states on the jQuery $.ajax
method?
回答1:
$.ajax() returns the XmlHttpRequest object, so if you really want to access it as the state changes, you can do this:
var xhr = $.ajax({ ... });
xhr.onreadystatechange = function() { alert(xhr.readyState); };
But the built-in callbacks should be all you need for most uses, particularly success
and complete
.
To do things before the request fires, use beforeSend
, or more appropriately for most cases, the .ajaxStart() and .ajaxStop() events...for example to show a loading message whenever any ajax activity is going on.
回答2:
Method, tested with jQuery 2.0.2:
$.ajax({
beforeSend: function (jqXHR, settings) {
var self = this;
var xhr = settings.xhr;
settings.xhr = function () {
var output = xhr();
output.onreadystatechange = function () {
if (typeof(self.readyStateChanged) == "function") {
self.readyStateChanged(this);
}
};
return output;
};
},
readyStateChanged: function (xhr) {
if (xhr.readyState == 1) {
/* Connected! Do something */
}
},
url: "..."
});
Basically, what I needed was a callback after readyState
becomes 1
(Connected), which, in my case, was useful when implementing long polling "push" notifications with jQuery.
回答3:
You should be able to get all you need by setting callbacks for the success
, error
, and complete
options in the object you pass into the ajax()
method. Take a look at the documentation:
http://api.jquery.com/jQuery.ajax/
Basically, it works like this:
$.ajax({
url: 'ajax/test.html',
success: function(data) {
alert('Load was performed.');
},
error: function() {alert("error occurred.")},
complete: function() {alert("ajax complete.")}
});
You can see the docs for exactly what parameters you have access to in the callback functions.
来源:https://stackoverflow.com/questions/4107909/jquery-ajax-and-readystates