问题
It is common to read until end of file, but I am interested in how could I read data (a series of numbers) from a text file until the end of a line? I got the task to read several series of numbers from a file, which are positioned in new lines. Here is an example of input:
1 2 53 7 27 8
67 5 2
1 56 9 100 2 3 13 101 78
First series: 1 2 53 7 27 8
Second one: 67 5 2
Third one: 1 56 9 100 2 3 13 101 78
I have to read them separately from file, but each one till the end of line. I have this code:
#include <stdio.h>
FILE *fp;
const char EOL = '\\0';
void main()
{
fp = fopen("26.txt", "r");
char buffer[128];
int a[100];
int i = 0;
freopen("26.txt","r",stdin);
while(scanf("%d",&a[i])==1 && buffer[i] != EOL)
i++;
int n = i;
fclose(stdin);
}
It reads until the end of the file, so it doesn't do quite what I would expect. What do you suggest?
回答1:
Use fgets() to read a full line, then parse the line (possibly with strtol()).
#include <stdio.h>
#include <stdlib.h>
int main(void) {
char buffer[10000];
char *pbuff;
int value;
while (1) {
if (!fgets(buffer, sizeof buffer, stdin)) break;
printf("Line contains");
pbuff = buffer;
while (1) {
if (*pbuff == '\n') break;
value = strtol(pbuff, &pbuff, 10);
printf(" %d", value);
}
printf("\n");
}
return 0;
}
You can see the code running at ideone.
回答2:
The \n should be the escape for new line, try this instead
const char EOL = '\n';
did u get it working? this should help:
#include <stdio.h>
FILE *fp;
const char EOL = '\n'; // unused . . .
void main()
{
fp = fopen("26.txt", "r");
char buffer[128];
int a[100];
int i = 0;
freopen("26.txt","r",stdin);
while(scanf("%i",&a[i])==1 && buffer[i] != EOF)
++i;
//print values parsed to int array.
for(int j=0; j<i; ++j)
printf("[%i]: %i\n",j,a[j]);
fclose(stdin);
}
来源:https://stackoverflow.com/questions/14001907/read-data-from-file-till-end-of-line-in-c-c