fopen

问题 I want my C program to ask the user to type the name of the file they want to open and print the contents of that file to the screen. I am working from the C tutorial and have the following code so far. But when I execute it, it doesn't actually allow me to enter the file name. (I get the 'press any button to continue', I am using codeblocks) What am I doing wrong here? #include <stdio.h> int main ( int argc, char *argv[] ) { printf("Enter the file name: \n"); //scanf if ( argc != 2 ) /* argc

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 3 years ago . Improve this question What is unsafe with fopen that's more safe with fopen_s ? How can fopen be used in a safe way (if possible)? (I don't want to know how to suppress the warning - there are enough stackoverflow articles that answer that question) Edit: Question was closed

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 3 years ago . Improve this question What is unsafe with fopen that's more safe with fopen_s ? How can fopen be used in a safe way (if possible)? (I don't want to know how to suppress the warning - there are enough stackoverflow articles that answer that question) Edit: Question was closed

问题 I have the following code: ptol = [2, 4, 8, ...]; a = ptol(1) fid = fopen( a,'r'); I need to open a file determined by which number is called from ptol , i.e. if ptol(1) = 2, then fopen should open file 2. Currently I get the error "invalid filename". How do I fix this? The following code is what I need to use to "load" the data in the files I'm struggling to open in to a matrix. fileName = strcat(num2str(a),'.ext'); file = fopen(fileName,'r'); count = 1; lines2skip = 4; mat = zeros(29,872);

问题 I am trying to open a file for reading in php script but having trouble. This is my code $fileHandle = fopen("1234_main.csv", "r")or die("Unable to open"); if (!file_exists($fileHandle)) { echo "Cannot find file."; } The script is in the same directory as the file I am trying to read and there are no other read/write permission errors as I can create/read other files in the same directory. When I run the script I just get the "Cannot find file" error message. Why is this error message being

问题 I have a problem with programming in C, especially with fopen in Visual Studio. I read about the fopen_s function and added the following line to my project, but it still doesn't work. _CRT_SECURE_NO_WARNINGS So I tried using fopen_s in this way: FILE *fp; errno_t err; if ((err = fopen_s(&fp, "C:/File.txt", "rt")) != 0) printf("File was not opened\n"); else fprintf(fp, "Date: %s, Time: %s, Score: %i \n", __DATE__, __TIME__, score); fclose(fp); It's still crashing. What's wrong? 回答1: You use

问题 I have a problem with programming in C, especially with fopen in Visual Studio. I read about the fopen_s function and added the following line to my project, but it still doesn't work. _CRT_SECURE_NO_WARNINGS So I tried using fopen_s in this way: FILE *fp; errno_t err; if ((err = fopen_s(&fp, "C:/File.txt", "rt")) != 0) printf("File was not opened\n"); else fprintf(fp, "Date: %s, Time: %s, Score: %i \n", __DATE__, __TIME__, score); fclose(fp); It's still crashing. What's wrong? 回答1: You use

问题 At some point in my code, I want to read a name for a file that I will be creating (and/or editing) and I've come up with the following: FILE *fp; char filename[15]; fgets(filename, 15, stdin); fp = fopen(filename, "a"); fprintf(fp, "some stuff goes here"); fclose(fp); Even though that does compile and run, it does not create (or open, if I manually create it) the file specified by filename . What would you suggest? 回答1: fgets() stores the newline character read from stdin after reading a

问题 At some point in my code, I want to read a name for a file that I will be creating (and/or editing) and I've come up with the following: FILE *fp; char filename[15]; fgets(filename, 15, stdin); fp = fopen(filename, "a"); fprintf(fp, "some stuff goes here"); fclose(fp); Even though that does compile and run, it does not create (or open, if I manually create it) the file specified by filename . What would you suggest? 回答1: fgets() stores the newline character read from stdin after reading a

问题 Is it possible to write data to CSV while the file is opened from desktop? Because I am trying to write some input data to CSV when user submit the form, but I am getting above error when the file is opened from my desktop. My system will only write to csv when I close the file. Error when meeting the line $fp = fopen("C:\Users\lenovo\Desktop\sample.csv", "w"); 回答1: Change the permission of the file sample.csv by using the following command on the terminal in the folder where the file is-