I've tried a few things already but they don't seem to work for some reason.
Basically what I'm attempting to do is have a user input a value using the "Read-host" cmdlet, then strip it of any spaces.
I tried:
$answer = read-host
$answer.replace(' ' , '""')
And:
$answer = read-host
$answer -replace (' ')
I'm probably missing something really obvious, but if anyone could help me out or show me an easier way to achieve this I would appreciate it.
I was going to pipeline the variable to a command and strip it in that fashion, but none of the examples I've seen work, although they look much easier.
The Replace
operator means Replace something with something else; do not be confused with removal functionality.
Also you should send the result processed by the operator to a variable or to another operator. Neither .Replace()
, nor -replace
modifies the original variable.
To remove all spaces, use 'Replace any space symbol with empty string'
$string = $string -replace '\s',''
To remove all spaces at the beginning and end of the line, and replace all double-and-more-spaces or tab symbols to spacebar symbol, use
$string = $string -replace '(^\s+|\s+$)','' -replace '\s+',' '
or the more native System.String
method
$string = $string.Trim()
Regexp is preferred, because ' '
means only 'spacebar' symbol, and '\s'
means 'spacebar, tab and other space symbols'. Note that $string.Replace()
does 'Normal' replace, and $string -replace
does RegEx replace, which is more heavy but more functional.
Note that RegEx have some special symbols like dot (.
), braces ([]()
), slashes (\
), hats (^
), mathematical signs (+-
) or dollar signs ($
) that need do be escaped. ( 'my.space.com' -replace '\.','-'
=> 'my-space-com'
. A dollar sign with a number (ex $1
) must be used on a right part with care
'2033' -replace '(\d+)',$( 'Data: $1')
Data: 2033
UPDATE: You can also use $str = $str.Trim()
, along with TrimEnd()
and TrimStart()
. Read more at System.String MSDN page.
You're close. You can strip the whitespace by using the replace
method like this:
$answer.replace(' ','')
There needs to be no space or characters between the second set of quotes in the replace method (replacing the whitespace with nothing).
You also have the Trim, TrimEnd and TrimStart methods of the System.String class. The trim method will strip whitespace (with a couple of Unicode quirks) from the leading and trailing portion of the string while allowing you to optionally specify the characters to remove.
#Note there are spaces at the beginning and end
Write-Host " ! This is a test string !%^ "
! This is a test string !%^
#Strips standard whitespace
Write-Host " ! This is a test string !%^ ".Trim()
! This is a test string !%^
#Strips the characters I specified
Write-Host " ! This is a test string !%^ ".Trim('!',' ')
This is a test string !%^
#Now removing ^ as well
Write-Host " ! This is a test string !%^ ".Trim('!',' ','^')
This is a test string !%
Write-Host " ! This is a test string !%^ ".Trim('!',' ','^','%')
This is a test string
#Powershell even casts strings to character arrays for you
Write-Host " ! This is a test string !%^ ".Trim('! ^%')
This is a test string
TrimStart and TrimEnd work the same way just only trimming the start or end of the string.
You can use:
$answer.replace(' ' , '')
or
$answer -replace " ", ""
if you want to remove all whitespace you can use:
$answer -replace "\s", ""
If the string is
$STR = 'HELLO WORLD'
and you want to remove the empty space between 'HELLO' and 'WORLD'
$STR.replace(' ','')
replace
takes the string and replaces white space with empty string (of length 0), in other words the white space is just deleted.
来源:https://stackoverflow.com/questions/24355760/removing-spaces-from-a-variable-input-using-powershell-4-0