python @abstractmethod decorator

Question

I have read python docs about abstract base classes:

From here:

abc.abstractmethod(function) A decorator indicating abstract methods.

Using this decorator requires that the class’s metaclass is ABCMeta or is derived from it. A class that has a metaclass derived from ABCMeta cannot be instantiated unless all of its abstract methods and properties are overridden.

And here

You can apply the @abstractmethod decorator to methods such as draw() that must be implemented; Python will then raise an exception for classes that don’t define the method. Note that the exception is only raised when you actually try to create an instance of a subclass lacking the method.

I've used this code to test that out:

import abc

class AbstractClass(object):
  __metaclass__ = abc.ABCMeta

  @abc.abstractmethod
  def abstractMethod(self):
    return

class ConcreteClass(AbstractClass):
  def __init__(self):
    self.me = "me"

c = ConcreteClass()
c.abstractMethod()

The code goes fine, so I don't get it. If I type c.abstractMethod I get:

<bound method ConcreteClass.abstractMethod of <__main__.ConcreteClass object at 0x7f694da1c3d0>>

What I'm missing here? ConcreteClass must implement the abstract methods, but I get no exception.

Answer 1

Are you using python3 to run that code ? if yes you should know that declaring metaclass in python 3 have changes you should do it like this instead:

import abc

class AbstractClass(metaclass=abc.ABCMeta):

  @abc.abstractmethod
  def abstractMethod(self):
      return