zipoutputstream

I am trying to read a single file from a java.util.zip.ZipInputStream , and copy it into a java.io.ByteArrayOutputStream (so that I can then create a java.io.ByteArrayInputStream and hand that to a 3rd party library that will end up closing the stream, and I don't want my ZipInputStream getting closed). I'm probably missing something basic here, but I never enter the while loop here: ByteArrayOutputStream streamBuilder = new ByteArrayOutputStream(); int bytesRead; byte[] tempBuffer = new byte[8192*2]; try { while ((bytesRead = zipStream.read(tempBuffer)) != -1) { streamBuilder.write(tempBuffer

ZipOutputStream only zips files in a folder. I want to zip subfolders also. How can I achieve this? You have to recursively explore your directory in order to add all files in the zip. See this small helper if you wish: using ICSharpCode.SharpZipLib.Zip; using ICSharpCode.SharpZipLib.Checksums; using System.IO; using System; using System.Collections.Generic; using System.Text; using System.Collections; using System.Text.RegularExpressions; namespace Zip { /// <summary> /// Uses Sharpziplib so as to create a non flat zip archive /// </summary> public abstract class ZipManager { /// <summary> //

I want to create .zip file that contains my zipped files that I recieve from backend, and then send this file to the user. For 2 days I have been looking for the answer and cant find proper solution, maybe you can help me :) For now, the code is like this: (I know I shouldnt do it all in the spring controller, but dont care about that, it is just for testing purposes, to find the way to make it works) @RequestMapping(value = "/zip") public byte[] zipFiles(HttpServletResponse response) throws IOException{ //setting headers response.setContentType("application/zip"); response.setStatus