word

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 5 years ago . I've tried to see if there were any scripts to convert a list of words into an array and I can't seem to find one. Anyone know where I can find one? Input: Dog Cat Hamster Gets converted to ["Dog", "Cat", "Hamster"] Noo.. this isn't what I mean. I have a txt file with a bunch of words on each line

问题 I am a beginner in c++. I have written a program to convert numbers into words. I am getting wrong output for numbers between 11-19 and numbers like this, 20,30,40,50,60,70,80,90. I also tried to add else statement between last two if statements so that It does not execute all the if statements even if the first if is true but it gives me an error that "else without a previous if". //This program converts number into words #include<iostream> using namespace std; main() { int number,unit,ten;

问题 How can I find a quick way to count the number of spacing between each word in a text? Each space represents a value, Example: one space is the letter 'a', two spaces is the letter 'b', etc.. An example with the text text : hello all the world one space between hello and all --> 'a', two spaces between all and the --> 'b', ... word --> 'abc' 回答1: import re import string ''.join(map(lambda x: string.lowercase[len(x) - 1], re.findall(r'\s+', 'hello all the world'))) # 'abc' 回答2: For

问题 I have been given a large text as input. I have made a HashMap that stores each different word as a key, and number of times that occurs as value (Integer). Now I have to make a method called mostOften(int k):List that return a List that gives the first k-words that from max number of occurrence to min number of occurrence ( descending order ) using the HashMap that I have made before. The problem is that whenever 2 words have the same number of occurrence, then they should be sorted

问题 I'm working on an application which has a workflow for postal mails. These postal mails are generated according to my application business rules. Models are in html or Rtf and it works perfectly as long the user do not create the rtf with word. This is not within the specs, but my hierarchy would welcome a Word compatibility if it don't involve too much work, and it would please and ease the life of our customer. The Rtf models have tags which are replaced by application values. In most RTF,

问题 I want to replace one random word of which are several in a string. So let's say the string is $str = 'I like blue, blue is my favorite colour because blue is very nice and blue is pretty'; And let's say I want to replace the word blue with red but only 2 times at random positions. So after a function is done the output could be like I like red, blue is my favorite colour because red is very nice and blue is pretty Another one could be I like blue, red is my favorite colour because blue is

问题 This question is an additional constraint on this this question. I wanted achieve the word count by avoiding multiple counts for that same word in the same file? Eg : if word "aaa" appears in "file1.txt" 10 times, but count should increase only by 1 but not 10 & so on for other files too within a directory. 回答1: So what you want is the number of files that contain that word. Easy: grep -l word *|wc -l 来源： https://stackoverflow.com/questions/19869272/how-to-count-occurrences-of-a-word-in-all

问题 I am currently working on a browsergame called "WordShuffle". (words are german at the moment for test purpose, if you want to play) My progress is going on pretty well, but I decieded to change the way how you play the game. At the moment you have to quess the word by typing your guess into a textfield. So my idea is now that people are able to rearrange the letters in a word by draging and dropping it in the right order instead of typing it into a textfield. Since I am not good at

问题 Okay. I am trying to add a word_tag, But I am not sure if this is the right way. (sorry I am a newbie) from nltk.corpus import wordnet as wn # Count the words word_count = Counter(words) # Clean the content a little filter_words = ['artists'] for word in filter_words: if word in word_count: del word_count[word] # POS_TAG the words word_tag = nltk.corpus.wn.synsets(word_count) # And the survey says... print("The Top {0} words".format(n)) for word, count, word_tag in word_count.most_common(n)