word

Regarding the Unix command “wc” what is considered as a word?

由 拟墨画扇 提交于 2019-12-10 23:08:27
问题 The command wc provides lineCount , wordCount , and charCount . I am writing a program that simulates the wc command as it takes a file and spits out the 3 properties. Line count is easy because if it sees \n it will ++lineCount and if a char exists and it's not EOF, it will ++charCount . But what does word mean? What separates words, whitespace? 回答1: This is specified by POSIX: The wc utility shall consider a word to be a non-zero-length string of characters delimited by white space. The man

How to calculate possible word subsequences matching a pattern?

由 南楼画角 提交于 2019-12-10 21:15:58
问题 Suppose I have a sequence: Seq = 'hello my name' and a string: Str = 'hello hello my friend, my awesome name is John, oh my god!' And then I look for matches for my sequence within the string, so I get the "word" index of each match for each word of the sequence in a cell array, so the first element is a cell containing the matches for 'hello', the second element contains the matches for 'my' and the third for 'name'. Match = {[1 2]; %'hello' matches [3 5 11]; %'my' matches [7]} %'name'

Counting words in javascript and push it into an object

由 微笑、不失礼 提交于 2019-12-10 18:28:22
问题 I want to achieve a javascript program that count through a word and return the word and the number of times it appears eg {hello : 2, "@hello":1, world : 1, toString:1} below is my code but i only get the total number of words function words(str) { app = {}; return str.split(" ").length; } console.log(words("hello world")); 回答1: Use reduce to iterate the words array, and count the instances: function words(str) { return str.split(" ").reduce(function(count, word) { count[word] = count

Word counts in Python using regular expression

由 人走茶凉 提交于 2019-12-10 17:44:11
问题 What is the correct way to count English words in a document using regular expression? I tried with: words=re.findall('\w+', open('text.txt').read().lower()) len(words) but it seems I am missing few words (compares to the word count in gedit). Am I doing it right? Thanks a lot! 回答1: Using \w+ won't correctly count words containing apostrophes or hyphens, eg "can't" will be counted as 2 words. It will also count numbers (strings of digits); "12,345" and "6.7" will each count as 2 words ("12"

Help me find the algorithm name - quantify difference between two words

由 蓝咒 提交于 2019-12-10 15:43:55
问题 I know there is an algorithm for seeing how "close" two words are together. The idea is that this algorithm adds 1 point to the score for every single letter addition or subtraction that is necessary to transform one word into the other. The lower this score, the "closer" the two words are together. For example, if we take the word "word" and "sword", their distance is 1. To go from "word" to "sword" all you have to do as add an "s" in the beginning. For "week" and "welk" the distance is 2.

Java: Regular expression where each character occurs 0-1 times

由 坚强是说给别人听的谎言 提交于 2019-12-10 14:06:45
问题 Problem: Match words in which each char of the regular expression occurs once at most. The word must be of a certain size, let's say "{2,5}" One specific char must be in the word, let's say char "e" What I've got: word.matches("^[abcde]{2,5}$"); This matches all words where the chars a, b, c, d, and e occur 0..5 times. Therefore the words "abba" and "dead" are matched even though "abba" uses the char "b" two times and "dead" uses the char "d" two times. The expression also ignores if the char

Android How to set maximum “word” limit on EditText

由 假装没事ソ 提交于 2019-12-10 13:17:43
问题 How to set maximum word limit on Android EditText I know how to set character limit but I am looking for Word Limit . 回答1: You need to add a TextChangedListener to your EditText then apply an InputFilter see the following code. edDesc.addTextChangedListener(new TextWatcher() { @Override public void onTextChanged(CharSequence s, int start, int before, int count) {} @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) { int wordsLength = countWords(s.toString

How to extract the common words before particular symbol and find particular word

由 …衆ロ難τιáo~ 提交于 2019-12-10 11:53:16
问题 IF I have a dictionary: mydict = {"g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt" : 0, "g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt" : 1, "g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt" : 2, "g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt" : 3, "g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt" : 4, "g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt" : 5, "h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt" : 6, "g18

Java, Number of n-words in a text

由 假装没事ソ 提交于 2019-12-10 11:49:22
问题 The purpose of this class is to count the number of occurrences of every n-character words in a text entered by the user. I think there are some mistakes in the method occurrenceNumber because I obtain 228 for every n-character word. Where is the error ? import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Scanner; public class TempTest { public static void main(String[] args) { BufferedReader in = new BufferedReader(new

Div Editable and More… More

由 杀马特。学长 韩版系。学妹 提交于 2019-12-08 15:24:32
Well, I need to replace a word, in a div contentEdible property on, by the same word but formatted... Like this: <div> My balls are big </div> To this (replace the word: balls): <div> My <font style="color:blue;">balls</font> are big </div> In a contentEditable this happens dinamically, while the user type the text the replacements happens. I think that a simple event onkeydown, onkeyup, or onkey press, can solve this part. But, the trouble is with the caret, that after all that i tryed, it stay before the word replaced, when should be stay after. I tryed write some js code, tryed find some
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