wait

Java Object.wait(long, long) Implementation different from Documentation

由 ￣綄美尐妖づ 提交于 2020-01-30 08:08:09
问题 The method Object#wait(long, long) in java.lang.Object states in it's documentation that This method is similar to the wait method of one argument, but it allows finer control over the amount of time to wait for a notification before giving up. The amount of real time, measured in nanoseconds, is given by: 1000000*timeout+nanos This in itself makes sense, but the implementation does not reflect the documentation: public final void wait(long timeout, int nanos) throws InterruptedException { //

puppeteer wait for network idle after click

由 白昼怎懂夜的黑 提交于 2020-01-24 19:31:09
问题 None of the existing Q&As have a clean solution for this question, e.g., puppeteer wait for page update after button click (no navigation) How can I wait for network idle after click on an element in puppeteer? So here is a simple working example for people to see/try/fix: const puppeteer = require('puppeteer'); (async() => { const browser = await puppeteer.launch({headless: true}); try { const page = await browser.newPage(); await page.setViewport({width: 800,height: 800}); const response =

线程定义、生命周期、常用方法

由 百般思念 提交于 2020-01-24 12:55:40
目录 一 线程的定义 1.1 概述 1.2 定义 二 interrupt 终止线程的方式 终止处于“阻塞状态”的线程 终止处于“运行状态”的线程 结合 interrupted() 和 isInterrupted()的区别 参考 三线程状态 四 常用方法 sleep和wait 参考 一 线程的定义 1.1 概述 线程是一个程序的多个执行路径，执行调度的单位，依托于进程存在 1.2 定义 1.继承Thread类 /** * 使用继承java.lang.Thread类的方式创建一个线程 * * @author DreamSea 2011-12-29 20:17:06 */ public class ThreadTest extends Thread { /** * 重写（Override）run()方法 JVM会自动调用该方法 */ public void run ( ) { System . out . println ( "I'm running!" ) ; } } 缺陷：不建议使用此方法定义线程，因为采用继承Thread的方式定义线程后，你 不能再继承 其他的类了，导致程序的可扩展性大大降低。 2.实现java.lang.Runnable接口 /** * 通过实现Runnable接口创建一个线程 * @author DreamSea */ public class

Implement wait between processes in Java?

由 拜拜、爱过 提交于 2020-01-24 10:46:49
问题 I would like some help understanding and implementing a 'wait until process complete' between the various processes in my application, which need to proceed in a step-wise fashion . My java file runs a batch file which then runs a script. At the conclusion of this there are series of commands that I need to run (through the command line) in a consecutive manner. I'm using: Runtime.getRuntime().exec("cmd /c start " + command) to run my batch files and commands (not sure if that information is

How to wait until speech is finished inside Loop?

由 一曲冷凌霜 提交于 2020-01-23 01:17:47
问题 I would like to halt/wait the for-loop until the window.speechSynthesis.speak(audio) finishes reading the text, then go to next iteration. I have below code: var all = "Oak is strong and also gives shade \n \ Cats and dogs each hate the other \n \ The pipe began to rust while new \n Bye." sentences = all.split('\n') for (i = 0; i < sentences.length; i++) { sentence = sentences[i] console.log(sentences[i]); audio = new SpeechSynthesisUtterance(sentence) window.speechSynthesis.speak(audio) }

Java: How can a thread wait on multiple objects?

由 [亡魂溺海] 提交于 2020-01-21 01:05:07
问题 A thread can use Object.wait() to block until another thread calls notify() or notifyAll() on that object. But what if a thread wants to wait until one of multiple objects is signaled? For example, my thread must wait until either a) bytes become available to read from an InputStream or b) an item is added to an ArrayList . How can the thread wait for either of these events to occur? EDIT This question deals with waiting for multiple threads to complete -- my case involves a thread waiting

How to use Fork() to create only 2 child processes?

由 孤街浪徒 提交于 2020-01-20 00:45:04
问题 I'm starting to learn some C and while studying the fork, wait functions I got to a unexpected output. At least for me. Is there any way to create only 2 child processes from the parent? Here my code: #include <sys/types.h> #include <stdio.h> #include <unistd.h> #include <sys/wait.h> int main () { /* Create the pipe */ int fd [2]; pipe(fd); pid_t pid; pid_t pidb; pid = fork (); pidb = fork (); if (pid < 0) { printf ("Fork Failed\n"); return -1; } else if (pid == 0) { //printf("I'm the child\n

Why the program didn't execute some sentences in this C programming or unix programming(execvp() System calls)?

由 假装没事ソ 提交于 2020-01-17 12:40:45
问题 I have the following program, when I run the program, I feel really confused that why my program didn't excute int num=i; printf("it is No.%d !",num); printf("hello , I will excute execvp!"); My program basically create 6 child processes to excute executionbode() function, and then use execvp to overload original program. However, everytime when I run the program, the string "hello, I will execute execvp" never shows up! Also I think those three sentences above also didn't execute in the

线程 Object线程的wait()参数和nofify()

由 允我心安 提交于 2020-01-16 06:59:46
1.wait（毫秒） 不用唤醒等毫秒过去后自己醒来了 2.notify() 唤醒一个单线程 3.notifyAl（） 唤醒多个线程 进入到TimeWaiting(记时等待)有两种方式 1.使用sleep(long m)方00法，在毫秒值结束之后，线程睡醒进入到Runnable/Blocked状态 2.使用wait(long m)方法如果在毫秒值结束之后，还没有被notify唤醒，就会自动醒来，相除睡醒进入到Runnable/Blocked状态 public class Demo01WaitAndNotify { public static void main ( String [ ] args ) { //创建锁对象，保证唯一 Object obj = new Object ( ) ; //创建一个顾客线程(消费者) new Thread ( ) { @Override public void run ( ) { while ( true ) { //保证等待和唤醒的线程只能有一个执行，需要使用同步技术 synchronized ( obj ) { System . out . println ( "顾客一告知老板要的保证和种类和数量" ) ; //调用wait方法，放弃cpu的执行，进入到WAITING状态(无限等待) try { obj . wait ( ) ; } catch

IO WAIT

由 Deadly 提交于 2020-01-15 08:34:48
定义：采样周期内 百分之几 属于以下情况——CPU空闲，并仍有空闲未完成的I/O请求 注：不表示CPU不能工作；不能表示I/O有瓶颈 eg1：CPU繁忙——不论I/O多少——IO WAIT 不变 CPU繁忙下降——一部分I/O落入CPU空闲时段——IO WAIT 提升 eg2：IO并发度 高——IO WAIT 低 IO并发度 低——IO WAIT 高 结论：IO WAIT升高，eg1不能证明等待IO的进程数量增多； eg2不能证明等待I/O总时长变多了； 来源： CSDN 作者： ang_yi 链接： https://blog.csdn.net/ang_yi/article/details/103910595
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