url-parameters

I have a requirement to design a RESTful Service using RESTEasy. Clients can call this common service with any number of Query Parameters they would want to. My REST code should be able to read these Query Params in some way. For example if I have a book search service, clients can make the following calls. http://domain.com/context/rest/books/searchBook?bookName=someBookName http://domain.com/context/rest/books/searchBook?authorName=someAuthor& pubName=somePublisher http://domain.com/context/rest/books/searchBook?isbn=213243 http://domain.com/context/rest/books/searchBook?authorName

I'm not really sure this belongs here, so instead of downvoting just lemme know if so and I'll quickly move it on. Anyway, there is a website that has a search page, that when hitting the search button it doesn't include the search query in the URL. After searching for something, the page is redirected to ssearch.asp , but as said, the query isn't there. My question is if there is a way to submit the search values solely via URL. I was wondering if there is a way to fake the search-submit button and post the search term via URL according to form field names. The name of the input box is search

The query part of a URL seems to consist of key-value pairs separated by & and associated by = . I've taken to always using jQuery's $.param() function to URL-encode my query strings because I find it makes my code more readable and maintainable. In the past couple of days I find myself calling the MediaWiki API but when cleaning up my working prototype with hard-coded URLs to use $.param() I noticed some MediaWiki APIs include query parameters with keys but not values! api.php ? action=query & titles=Main%20page & redirects Notice the part &redirects , which takes no value. jQuery's $.param()

How do you correctly add query parameters to a Dart http get request? I been unable to get my request to respond correctly when trying to append the '?param1=one&param2=two' to my url, yet it works correctly in Postman. Here's the gist of my code: final String url = "https://www.myurl.com/api/v1/test/"; String workingStringInPostman = "https://www.myurl.com/api/v1/test/123/?param1=one&param2=two"; Map<String, String> qParams = { 'param1': 'one', 'param2': 'two', }; var res = await http .get(Uri.encodeFull("$url${widget.pk}/"), headers: {HttpHeaders.authorizationHeader: "Token $token",

I'm currently creating a set of links with code like this: BookmarkablePageLink<CheeseMain> havarti = new BookmarkablePageLink<CheeseMain>("havarti", CheeseMain.class); havarti.setParameter("Title", "Havarti"); havarti.setParameter("Group", "cheeseName"); add(havarti); The URL that comes out has the format https://mysite.com/;jsessionid=B85EE5CB0349CCA2FE37AF76AB5C30C1?wicket:bookmarkablePage=:com.mycompany.cheese.CheeseMain&Title=Havarti&group=cheeseName . My problem is that I no longer want the URL for this link to be bookmarkable. Ideally, I would like it to be something simple like https:/

In a url like the one below, I'd like to get the value of ProdId. The URL format will always be consistent, as will the parameter name, but the length of the value may change. It will always be numeric. http://www.example.com/page.php?ProdId=2683322&xpage=2 Using PHP what's the fastest way to get it (I'll be processing 10,000's so speed is an issue)? PHP has built-in functions for this. Use parse_url() and parse_str() together. Pieced together from php.net: $url = 'http://www.example.com/page.php?ProdId=2683322&xpage=2'; // Parse the url into an array $url_parts = parse_url($url); // Parse the

For a project for my company, I have to send emails containing embedded URLs, which the user will be prompted to follow. For example, a person registers on the website, and then the Struts2 application sends an email to that person in which there is a URL to confirm the subscription. So far, the form submission, and sending the email (from inside the action), work just fine. The problem on which I'm stuck is that I can't find a way to generate the URL I'd like to embed in the mail body. I must be doing it the wrong way, but I was thinking about something like what follows: public String send()