uint

Background We've been using some code copied verbatim from Joe Duffy's "Concurrent Programming on Windows" (page 149) in production for over a year. The code (below) is used in our Asp.Net web application to probe if there's enough stack space. Our site allows users to script out their own web pages and control logic in a simple proprietry scripting language - it's possible for a user to script something nasty and cause a stackoverflow exception, so we use Duffy's code example to stop execution of the errant script before the uncatchable StackOverflow exception takes down the whole IIS AppPool

According to Swift - Converting String to Int , there's a String method toInt() . But, there's no toUInt() method. So, how to convert a String to a Uint ? Update for Swift 2/Xcode 7: As of Swift 2, all integer types have a (failable) constructor init?(_ text: String, radix: Int = default) which replaces the toInt() method of String , so no custom code is needed anymore for this task: print(UInt("1234")) // Optional(1234) // This is UInt.max on a 64-bit platform: print(UInt("18446744073709551615")) // Optional(18446744073709551615) print(UInt("18446744073709551616")) // nil (overflow) print

Following is the c# code: static void Main(string[] args) { uint y = 12; int x = -2; if (x > y) Console.WriteLine("x is greater"); else Console.WriteLine("y is greater"); } and this is c++ code: int _tmain(int argc, _TCHAR* argv[]) { unsigned int y = 12; int x = -2; if(x>y) printf("x is greater"); else printf("y is greater"); return 0; } Both are giving different result. Am I missing something basic? Any idea? C++ and C# are different languages. They have different rules for handling type promotion in the event of comparisons. In C++ and C, they're usually compared as if they were both

Suppose I have these variables, const uint8_t ndef_default_msg[33] = { 0xd1, 0x02, 0x1c, 0x53, 0x70, 0x91, 0x01, 0x09, 0x54, 0x02, 0x65, 0x6e, 0x4c, 0x69, 0x62, 0x6e, 0x66, 0x63, 0x51, 0x01, 0x0b, 0x55, 0x03, 0x6c, 0x69, 0x62, 0x6e, 0x66, 0x63, 0x2e, 0x6f, 0x72, 0x67 }; uint8_t *ndef_msg; char *ndef_input = NULL; How can I convert ndef_input (which is just a plain text, like "hello") to hex and save into ndef_msg ? As you can see ndef_default_msg is in hex form. Data inside ndef_msg should be something like that as well. A bit of background, in the original program ( source code ), the program

How do I get a uint unix timestamp in C++? I've googled a bit and it seems that most methods are looking for more convoluted ways to represent time. Can't I just get it as a uint ? Tony Delroy time() is the simplest function - seconds since Epoch. Linux manpage here . The cppreference page linked above gives this example : #include <ctime> #include <iostream> int main() { std::time_t result = std::time(nullptr); std::cout << std::asctime(std::localtime(&result)) << result << " seconds since the Epoch\n"; } #include<iostream> #include<ctime> int main() { std::time_t t = std::time(0); // t is an