问题
So I have this list, we'll call it listA. I'm trying to get the [3] item in each list e.g. ['5.01','5.88','2.10','9.45','17.58','2.76'] in sorted order. So the end result would start the entire list over again with Santa at the top. Does that make any sense?
[['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17.20', u'14.44', '2.76']]
回答1:
If you want to return the complete list in sorted order, this may work. This takes your input list and runs sorted on top of it. The reverse argument set to True sorts the list in reverse (descending) order, and the key argument specifies the method by which to sort, which in this case is the float of the third argument of each list:
In [5]: l = [['John Doe', u'25.78', u'20.77', '5.01'] # continues...
In [6]: sorted(l, reverse=True, key=lambda x: float(x[3]))
Out[6]:
[['Santa', u'31.13', u'13.55', '17.58'],
['Michael Jordan', u'28.50', u'19.05', '9.45'],
['Jane Doe', u'21.08', u'15.20', '5.88'],
['John Doe', u'25.78', u'20.77', '5.01'],
['Easter Bunny', u'17.20', u'14.44', '2.76'],
['James Bond', u'20.57', u'18.47', '2.10']]
If you only need the values in sorted order, the other answers provide viable ways of doing so.
回答2:
Try this:
>>> listA=[['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17.20', u'14.44', '2.76']]
>>> [x[3] for x in sorted(listA, reverse = True, key = lambda i : float(i[3]))]
['17.58', '9.45', '5.88', '5.01', '2.76', '2.10']
回答3:
An anonymous lambda function is not necessary for this task. You can use operator.itemgetter, which may be more intuitive:
from operator import itemgetter
res1 = sorted(map(itemgetter(3), listA), reverse=True, key=float)
['17.58', '9.45', '5.88', '5.01', '2.76', '2.10']
回答4:
from operator import itemgetter
lstA.sort(reverse = True, key = itemgetter(3))
And you are good to go. Using itemgetter() within a sort is extremely helpful when you have multiple indexs to sort on. Lets say you wanted to sort alphabetically on the first value in case of a tie you could do the following
from operator import itemgetter
lstA.sort(key = itemgetter(0))
lstA.sort(reverse = True, key = itemgetter(3))
And Voilà!
来源：https://stackoverflow.com/questions/13696281/sort-a-list-numerically-in-python