edit-distance

问题 In R, I have two character vectors, a and b. a <- c("abcdefg", "hijklmnop", "qrstuvwxyz") b <- c("abXdeXg", "hiXklXnoX", "Xrstuvwxyz") I want a function that counts the character mismatches between each element of a and the corresponding element of b. Using the example above, such a function should return c(2,3,1) . There is no need to align the strings. I need to compare each pair of strings character-by-character and count matches and/or mismatches in each pair. Does any such function exist

问题 Based on this paper: IEEE TRANSACTIONS ON PAITERN ANALYSIS : Computation of Normalized Edit Distance and Applications In this paper Normalized Edit Distance as followed: Given two strings X and Y over a finite alphabet, the normalized edit distance between X and Y, d( X , Y ) is defined as the minimum of W( P ) / L ( P )w, here P is an editing path between X and Y , W ( P ) is the sum of the weights of the elementary edit operations of P, and L(P) is the number of these operations (length of

问题 Based on this paper: IEEE TRANSACTIONS ON PAITERN ANALYSIS : Computation of Normalized Edit Distance and Applications In this paper Normalized Edit Distance as followed: Given two strings X and Y over a finite alphabet, the normalized edit distance between X and Y, d( X , Y ) is defined as the minimum of W( P ) / L ( P )w, here P is an editing path between X and Y , W ( P ) is the sum of the weights of the elementary edit operations of P, and L(P) is the number of these operations (length of

问题 Based on this paper: IEEE TRANSACTIONS ON PAITERN ANALYSIS : Computation of Normalized Edit Distance and Applications In this paper Normalized Edit Distance as followed: Given two strings X and Y over a finite alphabet, the normalized edit distance between X and Y, d( X , Y ) is defined as the minimum of W( P ) / L ( P )w, here P is an editing path between X and Y , W ( P ) is the sum of the weights of the elementary edit operations of P, and L(P) is the number of these operations (length of

问题 I'm trying to create a program that calculate edit distance between two files. I read with the funcution fread and I use the code to read binary ("rb"). I put in input two PDF files and during the debug I found out that when I try to fill the matrix of the Levenshtein distance algorithm I get a "SIGSEGV (Segmentation fault)" at char n° 1354 of the first file and the program exit with: Process finished with exit code -1073741819 (0xC0000005) I controlled and char n° 1354 is \n . The code that

问题 If the Levenshtein distance between two strings, s and t is given by L(s,t) , what is the difference in the impact on the resulting heuristic of the following two different normalization schemes? L(s,t) / [length(s) + length(t)] L(s,t) / max[length(s), length(t)] (L(s,t)*2) / [length(s) + length(t)] I noticed that normalization approach 2 is recommended by the Levenshtein distance Wikipedia page but no mention is made of approach 1. Are both approaches equally valid? Just wondering if there

问题 I'm trying to build a program that takes two strings and fills in the edit distance matrix for them. The thing that is tripping me up is, for the second string input, it is skipping over the second input. I've tried clearing the buffer with getch(), but it didn't work. I've also tried switching over to scanf(), but that resulted in some crashes as well. Help please! Code: #include <stdio.h> #include <stdlib.h> int min(int a, int b, int c){ if(a > b && a > c) return a; else if(b > a && b > c)

问题 I'm back with another longish question. Having experimented with a number of Python-based Damerau-Levenshtein edit distance implementations, I finally found the one listed below as editdistance_reference() . It seems to deliver correct results and appears to have an efficient implementation. So I set down to convert the code to Cython. on my test data, the reference method manages to deliver results for 11,000 comparisons (for pairs of words aound 12 letters long), while the Cythonized method

问题 Is there an algorithm that lets you find the word-level edit distance between 2 sentences? For eg., "A Big Fat Dog" and "The Big House with the Fat Dog" have 1 substitute, 3 insertions 回答1: You can use the same algorithms that are used for finding edit distance in strings to find edit distances in sentences. You can think of a sentence as a string drawn from an alphabet where each character is a word in the English language (assuming that spaces are used to mark where one "character" starts

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 5 years ago . Problem: I know the trivial edit distance DP formulation and computation in O(mn) for 2 strings of size n and m respectively. But I recently came to know that if we only need to calculate the minimum value of edit distance f and it is bounded |f|<=s, then we can calculate it in O