scientific-notation

问题 I just ran a statisitical model and i want it to display the results of the model as a table using stargazer. However, the large numbers are displayed in full. fit2<-lm(A~B,data=C) stargazer(fit2,type="text") With this table as result =================================================== Dependent variable: ------------------------------- A --------------------------------------------------- B -0.599 (1.698) 32,126,391.000 (24,004,268.000) ---------------------------------------------------

问题 I am writing a pandas df to a csv. When I write it to a csv file, some of the elements in one of the columns are being incorrectly converted to scientific notation/numbers. For example, col_1 has strings such as '104D59' in it. The strings are mostly represented as strings in the csv file, as they should be. However, occasional strings, such as '104E59', are being converted into scientific notation (e.g., 1.04 E 61) and represented as integers in the ensuing csv file. I am trying to export

问题 I'm using scientific notation in XAML. I do: <TextBox Text="{Binding Path=CELULARIDAD_CFU, StringFormat='e6'}"/> The problem is that for 1710000 is showing: 1.710000e+006, which is correct but I would like to see 1.71e+6. How is this specified in XAML? (Not in code) 回答1: I believe you should use the G format specifier to get (almost) what you want. <TextBox Text="{Binding Path=CELULARIDAD_CFU, StringFormat='G'}"/> Within a certain range (different for different number types, see link) the

问题 I would like to read and store scientific formatted numbers from a txt file, which is formatted and the numbers are separated by tabulator. This is what I have so far: IMPLICIT NONE REAL,ALLOCATABLE,DIMENSION(2) :: data(:,:) INTEGER :: row,column INTEGER :: j,i CHARACTER(len=30) :: filename CHARACTER(len=30) :: format filename='data.txt' open(86,file=filename,err=10) write(*,*)'open data file' read(86, *) row read(86, *) column allocate(data(row,column)) format='(ES14.7)' do i=1,row read(86

问题 I want to have Python2.7 print out floating point numbers in scientific notation, forced to start with 0. For instance, assume a=1234567890e12 print '{:22.16E}'.format(a) 1.2345678900000000E+21 However, I want a print output that looks like: 0.1234567890000000E+22 Notice that the exponent is raised by one since the desired output is forced to a leading zero. How can I achieve this? Thanks. 回答1: Well, since what you want to do is not "standard" scientific notation, I'm not sure if there is a

问题 I need to get the value of an extremely large number in JavaScript in non-exponential form. Number.toFixed simply returns it in exponential form as a string, which is worse than what I had. This is what Number.toFixed returns: >>> x = 1e+31 1e+31 >>> x.toFixed() "1e+31" Number.toPrecision also does not work: >>> x = 1e+31 1e+31 >>> x.toPrecision( 21 ) "9.99999999999999963590e+30" What I would like is: >>> x = 1e+31 1e+31 >>> x.toNotExponential() "10000000000000000000000000000000" I could

问题 When the numbers are really small, Matlab automatically shows them formatted in Scientific Notation. Example: A = rand(3) / 10000000000000000; A = 1.0e-016 * 0.6340 0.1077 0.6477 0.3012 0.7984 0.0551 0.5830 0.8751 0.9386 Is there some in-built function which returns the exponent? Something like: getExponent(A) = -16 ? I know this is sort of a stupid question, but I need to check hundreds of matrices and I can't seem to figure it out. Thank you for your help. 回答1: Basic math can tell you that:

问题 I'm making a function to return the number of decimal and whole number digits and am converting the inserted typename number to a string using sstream s. However the number when being converted to a string comes out in scientific notations which is not useful for counting the number of digits are in the normal number. How can I stop this from happening in my function below? enum { DECIMALS = 10, WHOLE_NUMBS = 20, ALL = 30 }; template < typename T > int Numbs_Digits(T numb, int scope) {

问题 I have problems working with large numbers and long decimal numbers, as others have mentioned or solved such issue using PrecisionEvaluate, I could not get consistent result with such function. Example with this code : <cfset n = 0.000000000009> <cfoutput>#precisionEvaluate(n)#</cfoutput> // this will produce "9E-12" <cfoutput>#precisionEvaluate("n")#</cfoutput> // this will produce "0.000000000009" According to Adobe Documentation, using Quote is not recommended (due to processing

问题 What's the proper way to convert from a scientific notation string such as "1.234567E-06" to a floating point variable using C#? 回答1: Double.Parse("1.234567E-06", System.Globalization.NumberStyles.Float); 回答2: Also consider using Double.TryParse("1.234567E-06", System.Globalization.NumberStyles.Float, out MyFloat); This will ensure that MyFloat is set to value 0 if, for whatever reason, the conversion could not be performed. Or you could wrap the Double.Parse() example in a Try..Catch block