问题
I want to have Python2.7 print out floating point numbers in scientific notation, forced to start with 0. For instance, assume
a=1234567890e12
print '{:22.16E}'.format(a)
1.2345678900000000E+21
However, I want a print output that looks like:
0.1234567890000000E+22
Notice that the exponent is raised by one since the desired output is forced to a leading zero. How can I achieve this? Thanks.
回答1:
Well, since what you want to do is not "standard" scientific notation, I'm not sure if there is a simple call to do this. Here is a hack, however, that will work
a = 1234567890e12
A = str(a)
exp = A.find('e+')
converted = '0.' + A[0] + A[2:exp] + 'e+' + str(int(A[exp+2:])+1)
回答2:
The fortranformat package will do what you are looking for.
import fortranformat as ff
a=1234567890e12
lineformat = ff.FortranRecordWriter('(1E26.16)')
lineformat.write([a])
Output:
' 0.1234567890000000E+22'
来源:https://stackoverflow.com/questions/21266850/python-scientific-notation-with-forced-leading-zero