round-robin

given table: create table Person( Name varchar(100) ) where Name is unique for all Persons What SQL query can generate all possible n!/((n-2)!2!) round robin combinations? It is assumed that the cardinality of Person is ALWAYS equal to 4 Example Person = {'Anna','Jerome','Patrick','Michael') Output: Anna, Jerome Anna, Patrick Anna, Michael Jerome, Patrick Jerome, Michael Patrick, Michael Any help would be appreciated. Thanks! Here's my answer (I used oracle SQL): select P1.NAME PERSON1, P2.NAME PERSON2 from (select rownum RNUM, NAME from PERSON) P1, (select rownum RNUM, NAME from PERSON) P2

So here's the question. While studying about process scheduling I came across two seemingly contradictory examples I just can't get my head around. The problem arises if for instance in the priority non-preemptive scheduling algorithm which always chooses the process with the highest priority to be run next and once running, process can only volontarily give up its CPU time, that is no other process can run until the currently running process finishes. It seems that what the solution the book proposes is that if both end of one process and arrival of the new high-priority process occur at the

Basically I have list of players, and I want to pair them up so that each player will play everyone once. What's the quickest way to find this data? assuming that players do not appear in the list twice, a double for loop is very quick: for (int i=0, i <= playerList.Count - 2, i++) for (int j=i+1, j <= playerList.Count - 1, j++) //add a new pairing of player i and j Such tournament schedule is often called round-robin . In wikipedia, there's also an example of possible scheduling algorithm . I put together 2 implementations to compare performance with. The very naive version 1 is about 50%

I am having some trouble to achieve this little round robin project. What i try to do is to generate a preview calendar of games then I want to output; day 1: Team 1 vs Team 2; Team 3 vs Team 4; Team 5vs Team 6; day 2 Team 1 vs Team 4; Team 6 vs Team 3; Team 2 vs Team 5; till the end of the championship; Here is the code i've got so far but i'm having trouble to let the first team fixed while the rest of the array rotates...: static void Main(string[] args) { string[] ListTeam = new string[] {"Equipe1", "Equipe2", "Equipe3", "Equipe4", "Equipe5", "Equipe6"}; IList<Match> ListMatch = new List

This question already has an answer here: A weighted version of random.choice 21 answers I need to return different values based on a weighted round-robin such that 1 in 20 gets A, 1 in 20 gets B, and the rest go to C. So: A => 5% B => 5% C => 90% Here's a basic version that appears to work: import random x = random.randint(1, 100) if x <= 5: return 'A' elif x > 5 and x <= 10: return 'B' else: return 'C' Is this algorithm correct? If so, can it be improved? Your algorithm is correct, how about something more elegant: import random my_list = ['A'] * 5 + ['B'] * 5 + ['C'] * 90 random.choice(my