round-robin | 易学教程

Evenly duplicate games to reach a maximum amount per participant

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问题 I have a round robin tournament where I create all the games necessary (7 games per participant) for 8 teams. I however need 10 games per participant which means I need to duplicate matchups, and on top of that 1 and 5 can't play each other. You can see from the data below the games I generated for each participant (# of games) in the order it was created which would be the round. I am trying to figure out the best possible way to duplicate the matchups and evently distribute the matchups in

How can we use multi-thread in round robin manner?

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问题 I want to read the unread mails of 10 mail accounts in a multi-thread way. But if the thread pool size is 5, then 5 threads will be used from the thread pool. Each thread will read one mail account. So once the Thread_1 has read the first mail box, it should read mailbox_6. Then thread 2 will read mailbox_7. When all mail account have been read once, the cycle will start from 1st mail account. How can we do this in java? 回答1: This should be pretty easy. You create a fixed-thread pool with 5

Implementing round robin scheduling algorithm in Java

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问题 After hours of braining I've finally crashed and have come to result that I have no clue how to implement round robin into java. I've tried different approaches and the closest I've got.. well i explain with an example.. AT = Arrival Time BT = Burst Time (Execution Time) At first i have this row of numbers (0,5;6,9;6,5;15,10) where elements in position 0-2-4 represent arrival times and elements in position 1-3-5 represent burst times. My code is so far that this input is turned into a class,

Round-robin algorithm in OCaml

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问题 This is the followup question of What's the grouping plan so that every two people are grouped together just once? Basically, I implemented the Round robin algorithm. By the algorithm, it can generate pairs list where each possible pair of elements are grouped together exactly once. For example, we have a, b, c, d , then On first day, we do a b c d Then we group like [(a,c);(b,d)]. Then we round it clockwise like a c d b Then we group like [(a,d);(c,b)]. Then we round it clockwise like a d b

Scheduling policies in Linux Kernel

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问题 Can there be more than two scheduling policies working at the same time in Linux Kernel ? Can FIFO and Round Robin be working on the same machine ? 回答1: Yes, Linux supports no less then 4 different scheduling methods for tasks: SCHED_BATCH, SCHED_FAIR, SCHED_FIFO and SCHED_RR. Regardless of scheduling method, all tasks also have a fixed hard priority (which is 0 for batch and fair and from 1- 99 for the RT schedulign methods of FIFO and RR). Tasks are first and foremost picked by priority -

Round-robin algorithm in OCaml

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This is the followup question of What's the grouping plan so that every two people are grouped together just once? Basically, I implemented the Round robin algorithm . By the algorithm, it can generate pairs list where each possible pair of elements are grouped together exactly once. For example, we have a, b, c, d , then On first day, we do a b c d Then we group like [(a,c);(b,d)]. Then we round it clockwise like a c d b Then we group like [(a,d);(c,b)]. Then we round it clockwise like a d b c Then we group like [(a,b);(d,c)]. (Note, a is fixed all the time.) Finally I can get [(a,c);(b,d)] [

SQL All Possible Round Robin Combinations between two Tables

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问题 given table: create table Person( Name varchar(100) ) where Name is unique for all Persons What SQL query can generate all possible n!/((n-2)!2!) round robin combinations? It is assumed that the cardinality of Person is ALWAYS equal to 4 Example Person = {'Anna','Jerome','Patrick','Michael') Output: Anna, Jerome Anna, Patrick Anna, Michael Jerome, Patrick Jerome, Michael Patrick, Michael Any help would be appreciated. Thanks! Here's my answer (I used oracle SQL): select P1.NAME PERSON1, P2

Evenly duplicate games to reach a maximum amount per participant

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I have a round robin tournament where I create all the games necessary (7 games per participant) for 8 teams. I however need 10 games per participant which means I need to duplicate matchups, and on top of that 1 and 5 can't play each other. You can see from the data below the games I generated for each participant (# of games) in the order it was created which would be the round. I am trying to figure out the best possible way to duplicate the matchups and evently distribute the matchups in such a way that there aren't matchups that duplicate three times and still retain 10 games per

RabbitMQ-发送消息方式Round-Robin

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When a Rabbit queue has multiple consumers, messages received by the queue are served in a round-robin fashion to the consumers. Each message is sent to only one consumer subscribed to the queue. Let’s say you had a queue named seed_bin and consumers Farmer Bob and Farmer Esmeralda subscribed to seed_bin. As messages arrive in seed_bin, the deliveries would look like this: 1 Message_A arrives in the seed_bin queue. 2 RabbitMQ sends Message_A to Farmer Bob. 3 Farmer Bob acknowledges receipt of Message_A. 4 RabbitMQ removes Message_A from the seed_bin queue. 5 Message_B arrives in the seed_bin

LINQ order by “round robin”

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Seems like this should be an easy task but I can't figure out how to do this with LINQ. The only information I've been able to find so far is regarding the round robin tournament format, which isn't what I'm after. I may be searching wrong. Given the following list: var items [] { "apple", "banana", "banana", "candy", "banana", "fruit", "apple" }; How can I sort this (preferably using linq) so that it comes out in "round robin" order, that is, select each unique item once before repeats. So the above list would come out like this (It's not important if it comes out in alphabetical order, even