repeat

问题 I need to send repeating messages from a list quickly and precisely. One list needs to send the messages every 100ms, with a +/- 10ms window. I tried using the code below, but the problem is that the timer waits the 100ms, and then all the computation needs to be done, making the timer fall out of the acceptable window. Simply decreasing the wait is a messy, and unreliable hack. The there is a Lock around the message loop in the event the list gets edited during the loop. Thoughts on how to

问题 This works as supposed, test fails (due to haltTesting()) and is repeated 2x public class A0001_A0003Test extends TestControl { private Kunde kunde = Kunde.FR_WEHLITZ; @Test(retryAnalyzer = TestRepeat.class, groups = {TestGroups.FAILED}, description = "verify adress") public void testkundenDaten_Angaben() throws Exception { bifiTestInitial(); testActions.selectKunde(kunde); haltTesting(); } } but because i have multiple tests in one class, i defined the repeatAnalyzer on class level @Test

问题 I'm using oracle to output line items in from a shopping app. Each item has a quantity field that may be greater than 1 and if it is, I'd like to return that row N times. Here's what I'm talking about for a table product_id, quanity 1, 3, 2, 5 And I'm looking a query that would return 1,3 1,3 1,3 2,5 2,5 2,5 2,5 2,5 Is this possible? I saw this answer for SQL Server 2005 and I'm looking for almost the exact thing in oracle. Building a dedicated numbers table is unfortunately not an option.

问题 How would one write a regex that matches a pattern that can contain quotes, but if it does, must have matching quotes at the beginning and end? "?(pattern)"? Will not work because it will allow patterns that begin with a quote but don't end with one. "(pattern)"|(pattern) Will work, but is repetitive. Is there a better way to do that without repeating the pattern? 回答1: You can get a solution without repeating by making use of backreferences and conditionals: /^(")?(pattern)(?(1)\1|)$/ Matches

问题 I am trying to define a function that accepts a point (x,y) as input, and returns an infinite list corresponding to recursively calling P = (u^2 − v^2 + x, 2uv + y) The initial values of u and v are both 0. The first call would be P = (0^2 - 0^2 + 1, 2(0)(0) + 2) = (1,2) Then that resulting tuple (1,2) would be the next values for u and v, so then it would be P = (1^2 - 2^2 + 1, 2(1)(2) + 2) = (-2,6) and so on. I'm trying to figure out how to code this in Haskell. This is what I have so far:

问题 I want to set repeat interval to the value which user selects from date picker.I have date picker of type countdown mode in my application.If user selects 4 hours 15 minutes from date picker then I am setting firedate using the following code and alarm rings. [NSDate dateWithTimeIntervalSinceNow:[pickerTimer countDownDuration]] But I want that notification should repeat after every 4 hours 15 minutes until user cancels it. I have done r&d searched a lot but I can not figure out.The code I

问题 I need some help in converting a 2X2 matrix to a 4X4 matrix in the following manner: A = [2 6; 8 4] should become: B = [2 2 6 6; 2 2 6 6; 8 8 4 4; 8 8 4 4] How would I do this? 回答1: A = [2 6; 8 4]; % arbitrary 2x2 input matrix B = repmat(A,2,2); % replicates rows & columns but not in the way you want B = B([1 3 2 4], :); % swaps rows 2 and 3 B = B(:, [1 3 2 4]); % swaps columns 2 and 3, and you're done! 回答2: In newer versions of MATLAB (R2015a and later) the easiest way to do this is using

问题 How can I run a function every minute? In JavaScript I can do something like setInterval , does something similar exist in Swift? Wanted output: Hello World once a minute... 回答1: var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true) func sayHello() { NSLog("hello World") } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector:

问题 How can I run a function every minute? In JavaScript I can do something like setInterval , does something similar exist in Swift? Wanted output: Hello World once a minute... 回答1: var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true) func sayHello() { NSLog("hello World") } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector:

问题 How can I run a function every minute? In JavaScript I can do something like setInterval , does something similar exist in Swift? Wanted output: Hello World once a minute... 回答1: var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true) func sayHello() { NSLog("hello World") } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: