repeat

问题 So I'm trying to ask the user if they would like to repeat my program and I am getting a weird result now and then. It doesn't happen everytime and I havn't been able to figure out what triggers it. To me it looks like it is assigning the 'return' after I enter 'q' to repeatProgram instead of the 'q' but I have no Idea why. The output when it works: to exit enter q, to continue enter y. s you've entered s, that isn't a valid option. The output when it fails: to exit enter q, to continue enter

问题 We created a JSF table component for our projects which uses <ui:repeat> to create the table. A new requirement to add a table inside a table (the second table resides in a row and is collapsable) has gotten us into trouble as the <ui:repeat var="row" ...> is set statically inside the table componenten and the inner table uses the row variable of the outer table when iterating through the list. Now what i want to create is something like this: <div> <myfw:mytable dataModel="#{bean.user}"

问题 I'm trying to create a MATLAB program to play a sound over and over again every couple of minutes. Right now I have it set to play every couple of seconds, just to get some bugs out of the system. However, when my program tries to replay the sound I get this error: ??? Error using ==> audioplayer.audioplayer>audioplayer.resume at 710 A given audio device may only be opened once. Error in ==> audioplayer.play at 88 obj.resume(); Error in ==> audiorecorder.audiorecorder>audiorecorder.play at

问题 I have a vector of values (say 1:10 ), and want to repeat certain values in it 2 or more times, determined by another vector (say c(3,4,6,8) ). In this example, the result would be c(1,2,3,3,4,4,5,6,6,7,8,8,9,10) when repeating 2 times. This should work for an arbitrary length range vector (like 200:600 ), with a second vector which is contained by the first. Is there a handy way to achieve this? 回答1: Akrun's is a more compact method, but this also will work # get rep vector reps <- rep(1L,

问题 I have the following method: public class ParentalControlInteractor { public Single<Boolean> isPinSet() { return bamSdk.getPinManager().isPINSet(); } } I want to call this function to run once, then repeat every minute until infinity but this seems clumsy: parentalControlInteractor.isPinSet() .subscribeOn(Schedulers.io()) .repeat(10000) .timeout(1600,TimeUnit.MILLISECONDS) .doOnError(throwable -> { Timber.e(throwable,"Error getting if Pin is set"); throwable.printStackTrace(); }) .subscribe

问题 I try to run a class method in Python 3 every n seconds. I thought that Threading would be a good approach. The question (Run certain code every n seconds) shows how to do that without objects. I tried to "transfer" this code to OOP like this: class Test: import threading def printit(): print("hello world") threading.Timer(5.0, self.printit).start() test = Test() test.printit() >> TypeError: printit() takes no arguments (1 given) I get this error. Can you help me doing it right? 回答1: Add the

问题 Suppose I have a list of data. For eg [1,2,3,4,5] and I have 1704 rows in my DataFrame. Now I want to add new column with this values only but it should be repeated till the last row as shown below: 1 2 3 4 5 1 2 3 4 5 .. and so on till the last record. I tried df['New Column']=pd.Series([1,2,3,4,5]) but it inserts record only in first 5 rows but I want this series to be repeated till the last. I referred many posts on SO but didn't found any relevant post. I am a newbie to pandas framework.

问题 I would like to generate a vector based on repeating the string "FST" but with a number at the end which increments: "Fst1" "Fst2" "Fst3" "Fst4" ... "Fst100" 回答1: An alternative to paste is sprintf , which can be a bit more convenient if, for instance, you wanted to "pad" your digits with leading zeroes. Here's an example: sprintf("Fst%d", 1:10) ## No padding # [1] "Fst1" "Fst2" "Fst3" "Fst4" "Fst5" # [6] "Fst6" "Fst7" "Fst8" "Fst9" "Fst10" sprintf("Fst%02d", 1:10) ## Pads anything less than

问题 I want to find ALL the paths starting and ending from/to a specific node. I would like that each node in a path appears only once. For example, in a graph like this: (a)-[:REL]->(b)-[:REL]->(c)-[:REL]->(a) (a)-[:REL]->(e)-[:REL]->(f)-[:REL]->(a) (e)-[:REL]->(b) grafically: e → b ↙ ↖ ↗ ↘ f → a ← c Cypher code: CREATE (a { name:'A' })-[:REL]->(b {name:'B'})-[:REL]->(c { name:'C' }) -[:REL]->(a)-[:REL]->(e {name:'E'})-[:REL]->(f {name:'F'})-[:REL]->(a), (e)-[:REL]->(b) I would like that the

问题 This is probably a really simple JSF question, but I can't seem to find the simple answer. I have a List of images, and I want to display them in a table of images. Each image is displayed with its filename. I'm using a ui:repeat tag as shown below. I don't get 5 columns as requested, however, only 1. <h:panelGrid id="resourcePanel" columns="5" rules="all"> <ui:repeat var="res" value="#{resourceUpload.resources}"> <h:panelGrid columns="1" rules="none"> <h:graphicImage value="/image/resource