reduce

来源： https://stackoverflow.com/questions/39788868/javascript-recursion-normalize-json-data

来源： https://stackoverflow.com/questions/63884077/how-does-one-categorize-a-list-of-data-items-via-many-different-category-lists-w

来源： https://stackoverflow.com/questions/60688086/javascript-reduce-need-function-that-makes-array-to-object

来源： https://stackoverflow.com/questions/48865040/pythonic-reduce-with-accumlation-and-arbitrary-lambda-function

来源： https://stackoverflow.com/questions/48865040/pythonic-reduce-with-accumlation-and-arbitrary-lambda-function

问题 I have following record set to process like 1000, 1001, 1002 to 1999, 2000, 2001, 2002 to 2999, 3000, 3001, 3002 to 3999 And I want to process the following record set using HIVE in such a way so that reducer-1 will process data 1000 to 1999 and reducer-2 will process data 2000 to 2999 and reducer-3 will process data 3000 to 3999.Please help me to solve above problem. 回答1: Use DISTRIBUTE BY , mappers output is being grouped according to the distribute by clause to be transferred to reducers

问题 The goal is to find a generic method to solve the following task: I have two python lists of the same length filled with zeros and ones : detection = [0,0,1,0] # only examples, they can be of any length ground_truth = [0,1,0,0] # and the ones can be at any indizes and a integer number offset = 1 # this number is also variable The goal is to combine # offset elements in detection around elements equal to 1 and then combine the same index elements of ground_truth logical or , resulting the new

问题 I have a list of dictionaries and each dictionary contains exactly the same keys. I want to find the average value for each key and I would like to know how to do it using reduce (or if not possible with another more elegant way than using nested for s). Here is the list: [ { "accuracy": 0.78, "f_measure": 0.8169374016795885, "precision": 0.8192088044235794, "recall": 0.8172222222222223 }, { "accuracy": 0.77, "f_measure": 0.8159133315763016, "precision": 0.8174754717495807, "recall": 0

问题 I have a list of dictionaries and each dictionary contains exactly the same keys. I want to find the average value for each key and I would like to know how to do it using reduce (or if not possible with another more elegant way than using nested for s). Here is the list: [ { "accuracy": 0.78, "f_measure": 0.8169374016795885, "precision": 0.8192088044235794, "recall": 0.8172222222222223 }, { "accuracy": 0.77, "f_measure": 0.8159133315763016, "precision": 0.8174754717495807, "recall": 0

问题 Code speaks better than language, so: ['a', 'b', 'c'].reduce((accumulator, value) => accumulator.concat(value), []); The code is very silly and returns a copied Array... TS complains on concat's argument: TS2345: Argument of type 'string' is not assignable to parameter of type 'ConcatArray'. 回答1: I believe this is because the type for [] is inferred to be never[] , which is the type for an array that MUST be empty. You can use a type cast to address this: ['a', 'b', 'c'].reduce((accumulator,