问题
Code speaks better than language, so:
['a', 'b', 'c'].reduce((accumulator, value) => accumulator.concat(value), []);
The code is very silly and returns a copied Array...
TS complains on concat's argument: TS2345: Argument of type 'string' is not assignable to parameter of type 'ConcatArray'.
回答1:
I believe this is because the type for [] is inferred to be never[], which is the type for an array that MUST be empty. You can use a type cast to address this:
['a', 'b', 'c'].reduce((accumulator, value) => accumulator.concat(value), [] as string[]);
Normally this wouldn't be much of a problem since TypeScript does a decent job at figuring out a better type to assign to an empty array based on what you do with it. However, since your example is 'silly' as you put it, TypeScript isn't able to make any inferences and leaves the type as never[].
来源：https://stackoverflow.com/questions/54117100/why-does-typescript-infer-the-never-type-when-reducing-an-array-with-concat