rbind

问题 following this post: (ShinyR : Insert user inputs in a database for further use), I found a solution to my problem, strongly inspired by this shiny app (https://deanattali.com/2015/06/14/mimicking-google-form-shiny/). I managed to get the main result I wanted (a database combining my observations and the results of the user of the app). Nonetheless I now have two new questions: First, how is it possible when looking at my code (complete version at the end of the post). Here are the lines from

问题 This is a follow up on my last question (Rbinding large list of dataframes after I did some data cleaning on the list). I've gotten smarter and the former question got messy. I have 43 xlsx files which I loaded in to a list in R: file.list <- list.files(recursive=T,pattern='*.xlsx') dat = lapply(file.list, function(i){ x = read_xlsx(i, sheet=1, col_names = T) # Create column with file name x$file = i # Return data x }) I then added some column names: my_names <- c("ID", "UDLIGNNR","BILAGNR",

问题 I'm working on a new function for the OEC package (https://cran.r-project.org/web/packages/oec/index.html) so I can batch download data. Here's my new function that I want to include in my package https://gist.github.com/pachamaltese/3b585dded0a80c031c65e98b268ebcc7 So, this is a MWE #install.packages("devtools") library(devtools) install_github("pachamaltese/oec/cran") library(oec) getdata_interval("chl","chn",2010,2014,6,2) Now I cannot find a general way to rbind the result of that

问题 My problem is, that I can't merge a large list of dataframes before doing some data cleaning. But it seems like my data cleaning is missing from the list. I have 43 xlsx-files, which I've put in a list. Here's my code for that part: file.list <- list.files(recursive=T,pattern='*.xlsx') dat = lapply(file.list, function(i){ x = read.xlsx(i, sheet=1, startRow=2, colNames = T, skipEmptyCols = T, skipEmptyRows = T) # Create column with file name x$file = i # Return data x }) I then did some

问题 I am trying to rbind pages sequentially by combining the data frames using the pages. library(jsonlite) pages <- list() for(i in 1:3){ mydata<- data.frame(c(1,2), c(4,5)) pages[[i+1]] <- mydata$filings } filings <- rbind.pages(pages) When i view the filings dataset I see only 0 variables. I am expecting 6 rows and 2 columns. Can some one address how to tether and attach the data while looping. Thanks 来源： https://stackoverflow.com/questions/30539282/combining-many-data-frames-with-rbind-and

问题 I've used data.table to create an empty data frame but when I'm adding observations to it all the observations after the first one get coerced to NA. First I create an empty data frame using the "stringsAsFactors = FALSE" parameter: cards <- data.frame(Ending = character(), Owner = character(), stringsAsFactors = FALSE) str(cards) 'data.frame': 0 obs. of 2 variables: $ Ending: chr $ Owner : chr I get a data frame with 0 observations and two character variables as expected. Then I create

问题 I am trying to append more than 10 000 files into a data frame in R. The first step in this job was to scrape files from for(i in 1:10000) { assign(x = paste("data", i, sep = "_"), value = readHTMLTable((paste("webaddress_page=", i, sep = '')),which=1)) } This works just fine, and I have 10 000 files, data_1-data_10000. However, I would like to append these files into a data.frame, but not sure how to proceed? Do I add another "data step", or maybe it is possible to do within the existing

问题 var1 var2 var3 1 2 3 1 2 3 1 2 3 I want to stack var2 and var3 underneath var1 to get: var1 1 1 1 2 2 2 3 3 3 I tried: data$var <- append(data$var1,data$var2) Then I get an error that my replacement has more rows. How do I solve this? 回答1: df <- data.frame(var1=1:3,var2=4:6,var3=7:9) df2 <- stack(df) print(df2) values ind 1 1 var1 2 2 var1 3 3 var1 4 4 var2 5 5 var2 6 6 var2 7 7 var3 8 8 var3 9 9 var3 回答2: You may want to try unlist : dtf <- data.frame(a = 1:3, b = 1:3, c = 1:3) unlist(dtf)

问题 Let's say I have an unspecified number of vectors of different lengths, and I want to effectively rbind them together, with the caveat that they must each occupy a different column in the resulting data.frame. You may assume that the vectors are contained in a list, but you cannot depend on any component names that may be defined within the list. Below I present a random sample input ( lv ) and a poor solution to generate the required output that manually builds the resulting data.frame by

问题 I have some JSON that looks like this: "total_rows":141,"offset":0,"rows":[ {"id":"1","key":"a","value":{"SP$Sale_Price":"240000","CONTRACTDATE$Contract_Date":"2006-10-26T05:00:00"}}, {"id":"2","key":"b","value":{"SP$Sale_Price":"2000000","CONTRACTDATE$Contract_Date":"2006-08-22T05:00:00"}}, {"id":"3","key":"c","value":{"SP$Sale_Price":"780000","CONTRACTDATE$Contract_Date":"2007-01-18T06:00:00"}}, ... In R, what would be the easiest way to produce a scatter-plot of SP$Sale_Price versus