octal

I have this little homework assignment and I needed to convert decimal to octal and then octal to decimal. I did the first part and can not figure out the second to save my life. The first part went like this: decimal = int(input("Enter a decimal integer greater than 0: ")) print("Quotient Remainder Octal") bstring = " " while decimal > 0: remainder = decimal % 8 decimal = decimal // 8 bstring = str(remainder) + bstring print ("%5d%8d%12s" % (decimal, remainder, bstring)) print("The octal representation is", bstring) I read how to convert it here: Octal to Decimal but have no clue how to turn

I'm trying to make an array of zip codes. array = [07001, 07920] This returns : array = [07001, 07920] ^ from (irb):12 from :0 Never seen this before. Any workarounds? Yuliy Ruby is interpreting numbers that have a leading 0 as being in octal (base 8). Thus the digits 8 and 9 are not valid. It probably makes more sense to store ZIP codes as strings, instead of as numbers (to avoid having to pad with zeroes whenever you display it), as such: array = ["07001", "07920"] Numbers that start with 0 are assumed to be in octal format, just like numbers that start with 0x are assumed to be in

I haven't learned this in programming class before, but now I need to know it. What are some good resources for learning these numbers and how to convert them? I pretty much am going to memorise these like the times table. In our everyday decimal system, the base number, or radix is 10 . A number system's radix tells us how many different digits are in use . In decimal system we use digits 0 through 9 . The significance of a digit is radix ^ i , where i is digit's position counting from right, starting at zero. Decimal number 6789 broken down: 6 7 8 9 radix ^ i | | | | -------------- | | | +--

Possible Duplicate: Decimal Conversion error I am writing a program for a class and is having trouble figuring how to convert an octal number to an decimal number. Here is what I been trying to do so far: import java.util.Scanner; public class test { public static void main ( String args[]) { Scanner input = new Scanner(System.in); System.out.print("Enter number: "); int oct = input.nextInt(); int d2count = 0; int result=0; int d3count = 0; int d3 = 0; int d2 = 0; d3 = oct; d2 = oct; if(oct < 1000){ while ( d3 >= 100){ d3 = d3 - 100; d3count++; }} if (oct < 100){ while ( d2 >= 10){ d2 = d2 -

1. script: $num = "00445790"; echo $num; returns: 00445790 2. script $num = 00445790; echo $num; returns: 2351 Can somebody explain why I get 2351 on the second script? John Conde Integers that start with zero are consider octal. Because octal integers only use numbers from 0 to 8 everything from the 9 on are ignored. So 00445790 becomes 004457 which is 2351 in decimal. 来源： https://stackoverflow.com/questions/30629817/weird-output-when-number-starts-with-0