octal

AJAX Asp.net AutoCompleteExtender interpreting string 0010 as octal

跟風遠走 提交于 2019-12-02 01:22:36
I'm using the MS AJAX AutoCompleteExtender on a textbox. It's working fine, except when the web service returns strings like "0010" -- in which case, it displays "8". I eventually realised it was interpreting the string "0010" as an octal number (and then proved the point by adding strings like "0100" and "0x10".) How can I prevent this? If the web service returns "0010", I want the autocomplete extender to also display "0010", and not interpret it as octal and display a decimal equivalent. Single quote it. JavaScript makes it an int. 来源: https://stackoverflow.com/questions/382063/ajax-asp-net

How do I convert an octal number to decimal in Ruby?

一曲冷凌霜 提交于 2019-12-01 23:09:30
问题 I am trying to find a clean way of referencing an array's index using octal numbering. If I am looking for the array index that is octal 13 it should return the value for a[11] . This is what I have come up with to accomplish it, but it doesn't seem very elegant or efficient: a = [ 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62 ] v = 13 puts a[v.to_s.to_i(8)] # => 61 # OR puts a[v.to_s.oct] # => 61 Is there a better way? 回答1: Use Ruby's octal integer literal syntax. Place a 0 before your

When displaying the value of variable “int a = 011”, I get 9. Why? [duplicate]

这一生的挚爱 提交于 2019-12-01 22:20:28
This question already has an answer here: What does it mean when a numeric constant in C/C++ is prefixed with a 0? 7 answers printf with “%d” of numbers starting with 0 (ex “0102”) giving unexpected answer (ex '“66”) 3 answers With this code snippet: int a = 011; printf("a = %d", a); Why is the result a = 9 011 is an octal value and its decimal equivalent is 9. Preceding integer literal with 0 indicates octal value. Use %o specifier in printf to print the value in octal. A leading 0 , in an int literal or int constant, represents the octal value. It is called an octal constant. Related: C11

How do I convert an octal number to decimal in Ruby?

你。 提交于 2019-12-01 21:53:41
I am trying to find a clean way of referencing an array's index using octal numbering. If I am looking for the array index that is octal 13 it should return the value for a[11] . This is what I have come up with to accomplish it, but it doesn't seem very elegant or efficient: a = [ 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62 ] v = 13 puts a[v.to_s.to_i(8)] # => 61 # OR puts a[v.to_s.oct] # => 61 Is there a better way? Use Ruby's octal integer literal syntax. Place a 0 before your number, and Ruby will convert it to octal while parsing: v = 013 # => 11 a[v] # => 61 If the octal number is

Why do Java octal escapes only go up to 255?

落花浮王杯 提交于 2019-12-01 17:18:45
The Java language specification states that the escapes inside strings are the "normal" C ones like \n and \t , but they also specify octal escapes from \0 to \377 . Specifically, the JLS states: OctalEscape: \ OctalDigit \ OctalDigit OctalDigit \ ZeroToThree OctalDigit OctalDigit OctalDigit: one of 0 1 2 3 4 5 6 7 ZeroToThree: one of 0 1 2 3 meaning that something like \4715 is illegal, despite it being within the range of a Java character (since Java characters are not bytes). Why does Java have this arbitrary restriction? How are you meant to specify octal codes for characters beyond 255?

how to avoid python numeric literals beginning with “0” being treated as octal?

这一生的挚爱 提交于 2019-12-01 16:27:34
I am trying to write a small Python 2.x API to support fetching a job by jobNumber , where jobNumber is provided as an integer. Sometimes the users provide a jobNumber as an integer literal beginning with 0, e.g. 037537 . (This is because they have been coddled by R, a language that sanely considers 037537==37537 .) Python, however, considers integer literals starting with "0" to be OCTAL, thus 037537!=37537 , instead 037537==16223 . This strikes me as a blatant affront to the principle of least surprise, and thankfully it looks like this was fixed in Python 3---see PEP 3127 . But I'm stuck

Change '0777' string to 0777 octal LITERALLY

二次信任 提交于 2019-12-01 05:33:18
My code is like $perm = "0777"; //this is fetch from the database chmod("myFolder/", $perm); but the value of $perm is not in octal, how can I change the data type of the variable to octal? even an alternative method will do As it was mentioned, there is no octal number type. And chmod function receive the second param as integer number. Implicit conversion of $perm does not assume that number is octal. So, you need convert your "octal string" to integer by using appropriate function. Just use octdec function $perm = "0777"; //this is fetch from the database chmod("myFolder/", octdec($perm));

Working with PHP Octals and String conversions

99封情书 提交于 2019-12-01 05:27:00
I'm working with a database that has a bunch of serial numbers that are prefixed with leading 0's. So a serial number can look like 00032432 or 56332432. Problem is with PHP I don't understand how the conversion system with octals works. A specific example is that I'm trying to convert and compare all of these integer based numbers with strings. Is it possible to convert an octal, such as 00234 to a string like "00234" so that I can compare it? edit - adding a specific example. I would like to be able to run str functions on the serial like below. $serial = 00032432; // coming from DB if

Change '0777' string to 0777 octal LITERALLY

别来无恙 提交于 2019-12-01 03:59:47
问题 My code is like $perm = "0777"; //this is fetch from the database chmod("myFolder/", $perm); but the value of $perm is not in octal, how can I change the data type of the variable to octal? even an alternative method will do 回答1: As it was mentioned, there is no octal number type. And chmod function receive the second param as integer number. Implicit conversion of $perm does not assume that number is octal. So, you need convert your "octal string" to integer by using appropriate function.

What does an extra 0 in front of an int value mean?

半城伤御伤魂 提交于 2019-11-30 15:54:49
问题 Inspiring from a obfuscated piece of code, I have a small question regarding to assign value to an integer: #include <iostream> #include <cstdio> int main() { int i = 0101; std::cout << i << "\n"; } And the output was 65, and I have no idea where 65 came from? Any idea? 回答1: It specifies an octal (base-8) number: 0101 == 1 * (8 * 8) + 1 == 65 . 回答2: Lambert already explained that. So let me tell you what else you can do. You can write hexadecimal integer: int main() { int i = 0x101; //0x