loops

问题 I think this is very easy but I have no idea how to do it (or how to search it). Okay so I got 378 observations for a lot of countries. It goes like this ISO3C Date Country Vaccines Tests Confirmed Recovered Death Hospitalized Ventilation ICU 1 AFG 2020-01-01 Afghanistan 0 0 0 0 0 0 0 0 2 AFG 2020-01-02 Afghanistan 0 0 0 0 0 0 0 0 3 AFG 2020-01-03 Afghanistan 0 0 0 0 0 0 0 0 4 AFG 2020-01-04 Afghanistan 0 0 0 0 0 0 0 0 5 AFG 2020-01-05 Afghanistan 0 0 0 0 0 0 0 0 So How do I set a counter

问题 I think this is very easy but I have no idea how to do it (or how to search it). Okay so I got 378 observations for a lot of countries. It goes like this ISO3C Date Country Vaccines Tests Confirmed Recovered Death Hospitalized Ventilation ICU 1 AFG 2020-01-01 Afghanistan 0 0 0 0 0 0 0 0 2 AFG 2020-01-02 Afghanistan 0 0 0 0 0 0 0 0 3 AFG 2020-01-03 Afghanistan 0 0 0 0 0 0 0 0 4 AFG 2020-01-04 Afghanistan 0 0 0 0 0 0 0 0 5 AFG 2020-01-05 Afghanistan 0 0 0 0 0 0 0 0 So How do I set a counter

问题 I have this for loop: for($i=0; $i < $N; $i++) $require_1 .= $require[$i] . " "; I would like it to place a comma on the end of the first word, if there's 2 words in the string. However if there's only 1 word in the string I want it left alone. I understand I need to use an if statement, based on $i . However I'm not sure how I do this. 回答1: This is a trick I use a lot to make strings like that, $require_1 = ""; for ($i = 0; $i < $N; $i++) { if ($require_1 == '' || $require_1 == '&') {

问题 I have this for loop: for($i=0; $i < $N; $i++) $require_1 .= $require[$i] . " "; I would like it to place a comma on the end of the first word, if there's 2 words in the string. However if there's only 1 word in the string I want it left alone. I understand I need to use an if statement, based on $i . However I'm not sure how I do this. 回答1: This is a trick I use a lot to make strings like that, $require_1 = ""; for ($i = 0; $i < $N; $i++) { if ($require_1 == '' || $require_1 == '&') {

问题 I have this for loop: for($i=0; $i < $N; $i++) $require_1 .= $require[$i] . " "; I would like it to place a comma on the end of the first word, if there's 2 words in the string. However if there's only 1 word in the string I want it left alone. I understand I need to use an if statement, based on $i . However I'm not sure how I do this. 回答1: This is a trick I use a lot to make strings like that, $require_1 = ""; for ($i = 0; $i < $N; $i++) { if ($require_1 == '' || $require_1 == '&') {

问题 Aloha, Introduction The idea is to create a quiz game in which you have a varying amount of buttons, one answer is "right" the others are "wrong". When selecting any button the color of the "right button" should turn green, the rest turn red. How the App works The App loads all the data from a Swift file called LectureTopics (See Below). LectureTopics is a struct that contains a lot of variables (ButtonText, ButtoneAnswerCorrect (Bool) Descriptions etc.) and an extension that holds the

问题 Aloha, Introduction The idea is to create a quiz game in which you have a varying amount of buttons, one answer is "right" the others are "wrong". When selecting any button the color of the "right button" should turn green, the rest turn red. How the App works The App loads all the data from a Swift file called LectureTopics (See Below). LectureTopics is a struct that contains a lot of variables (ButtonText, ButtoneAnswerCorrect (Bool) Descriptions etc.) and an extension that holds the

问题 I'd like to be able to change the number of loops and store all possibilities in a (list of lists). Let me explain by an example: You have the following list: initial_list=[1,2] Then you have a parameter n, which is the number of loops For example if n=2, I'd like my programm to return this list: final_list=[[x,x,1,2],[x,1,x,2],[x,1,2,x],[1,x,x,2],[1,x,2,x][1,2,x,x]] So for n=3, the program would do the same with 3 'x', etc Also, i'd like my initial_list could have different length, like [1,2

问题 I am new to coding in C. I am trying to write a code that finds the peak number in an array, that is the numbers that are greater than the numbers before and after said number. This is my code. It runs without error but no output so I know I am doing something wrong. #include <stdio.h> int main() { int nums[14] = {1, 2, 3, 3, 2, 4, 1, 5, 6, 3, 1, 10, 2, 8}; int peaks[4]; for(int i = 0; i < nums[i]; i++){ if(nums[i] > nums[i-1] && nums[i] > nums[i+1]){ peaks == nums[i]; } return peaks; }

问题 I have a function with including if, else condition and for loop. I want to write this function inside a lambda expression. I tried from many ways to create this lambda function. But still I couldn't do it. This is my function with another rules. negation ='no,not,never'.split(',') list2 = 'miss,loss,gone,give up,lost'.split(',') def f(sentence): s = sentence.split() l = [s.index(word) for word in s if word in list2] # Will returns list of indices (of sentence) where word is in list2 if len(l