PHP for loop adding commas

问题

I have this for loop:

for($i=0; $i < $N; $i++)
   $require_1 .= $require[$i] . " ";

I would like it to place a comma on the end of the first word, if there's 2 words in the string. However if there's only 1 word in the string I want it left alone.

I understand I need to use an if statement, based on $i. However I'm not sure how I do this.

回答1:

This is a trick I use a lot to make strings like that,

$require_1 = "";
for ($i = 0; $i < $N; $i++) {
    if ($require_1 == '' || $require_1 == '&') {
        $require_1 .= $require[$i];
    }
    else {
        $require_1 .= ', '.$require[$i];
    }
}

edit - added another condition for '&' char

回答2:

$require_1 = implode(', ', $require);

Will this do? It places a comma and a space after each item

回答3:

for($i=0; $i < $N; $i++) {
    $require[$i] = explode(' ', $require[$i]);
    $require[$i] = implode(', ', $require[$i]);
    $require_1 .= $require[$i] . " ";
}

this will break up each string, and add commas beteen each word.

来源：https://stackoverflow.com/questions/4702563/php-for-loop-adding-commas